6. ZigZag Conversion
作者:
wtmxx | 来源:发表于
2018-02-01 22:46 被阅读0次class Solution {
public String convert(String s, int numRows) {
int len = s.length();
if(numRows<2||len==0){
return s;
}
int d = 2*numRows-2;
String res = "";
for(int row = 0;row<numRows&&row<len;row++){
int i = row;
if(row==0||row==numRows-1){
while(i<len){
res+=s.charAt(i);
i+=d;
}
}else{
res+=s.charAt(i);
i+=d-2*row;
while(i<len){
res+=s.charAt(i);
i+=2*row;
if(i>=len)
break;
res+=s.charAt(i);
i+=d-2*row;
}
}
}
return res;
}
}
本文标题:6. ZigZag Conversion
本文链接:https://www.haomeiwen.com/subject/rkgjzxtx.html
网友评论