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GO语言学习笔记6-Sort的使用

GO语言学习笔记6-Sort的使用

作者: Codeapes | 来源:发表于2019-11-30 19:14 被阅读0次

    GoLang标准库的sort包提供了排序切片和用户自定义数据集以及相关功能的函数。

    Sort操作的对象通常是一个slice,需要满足三个基本的接口,并且能够使用整数来索引。

    1.sort实现原理

    Sort排序的函数原型如下所示:

    1.1 Sort

    // It makes one call to data.Len to determine n, and O(n*log(n)) calls to
    // data.Less and data.Swap. The sort is not guaranteed to be stable.
    func Sort(data Interface) {
        n := data.Len()
        quickSort(data, 0, n, maxDepth(n))
    }
    

    1.2 interface

    // A type, typically a collection, that satisfies sort.Interface can be
    // sorted by the routines in this package. The methods require that the
    // elements of the collection be enumerated by an integer index.
    type Interface interface {
        // Len is the number of elements in the collection.
        Len() int
        // Less reports whether the element with
        // index i should sort before the element with index j.
        Less(i, j int) bool
        // Swap swaps the elements with indexes i and j.
        Swap(i, j int)
    }
    

    1.3 quickSort

    func quickSort(data Interface, a, b, maxDepth int) {
        for b-a > 12 { // Use ShellSort for slices <= 12 elements
            if maxDepth == 0 {
                heapSort(data, a, b)
                return
            }
            maxDepth--
            mlo, mhi := doPivot(data, a, b)
            // Avoiding recursion on the larger subproblem guarantees
            // a stack depth of at most lg(b-a).
            if mlo-a < b-mhi {
                quickSort(data, a, mlo, maxDepth)
                a = mhi // i.e., quickSort(data, mhi, b)
            } else {
                quickSort(data, mhi, b, maxDepth)
                b = mlo // i.e., quickSort(data, a, mlo)
            }
        }
        if b-a > 1 {
            // Do ShellSort pass with gap 6
            // It could be written in this simplified form cause b-a <= 12
            for i := a + 6; i < b; i++ {
                if data.Less(i, i-6) {
                    data.Swap(i, i-6)
                }
            }
            insertionSort(data, a, b)
        }
    }
    

    2.Sort内部 []int排序

    type IntSlice []int
    // 获取此 slice 的长度
    func (p IntSlice) Len() int           { return len(p) }
    
    // 比较两个元素大小,升序
    func (p IntSlice) Less(i, j int) bool { return p[i] < p[j] }
    
    // 交换数据
    func (p IntSlice) Swap(i, j int)      { p[i], p[j] = p[j], p[i] }
    
    // Sort is a convenience method.
    func (p IntSlice) Sort() { Sort(p) }
    

    3.代码实现

    Olymic Game这道题采用Sort排序的实现方法如下:

    package main
    
    import (
        "fmt"
        "sort"
        "strings"
    )
    
    type MedalNum struct {
        name string
        gold int
        silver int
        bronze int
    }
    
    type MedalNumList []MedalNum
    
    func (m MedalNumList) Len() int {
        return len(m)
    }
    
    // 奖牌数降序,国家名称字典序
    func (m MedalNumList) Less(i, j int) bool {
        if m[i].gold > m[j].gold {
            return true
        } else if m[i].gold == m[j].gold {
            if m[i].silver > m[j].silver {
                return true
            } else if m[i].silver == m[j].silver {
                if m[i].bronze > m[j].bronze {
                    return true
                } else if m[i].bronze == m[j].bronze {
                    if strings.Compare(m[i].name, m[j].name) < 0 {
                        return true
                    }
                }
            }
    
        }
        return false
    }
    
    func (m MedalNumList) Swap(i, j int) {
        m[i], m[j] = m[j], m[i]
    }
    
    func main() {
        var n int
    
        _, _ = fmt.Scan(&n)
    
        var medal MedalNumList
    
        var nameI string
        var goldI, sliverI, bronzeI int
    
        i := 0
        for {
            if i == n {
                break
            }
            _, err := fmt.Scanln(&nameI, &goldI, &sliverI, &bronzeI);
    
            if err != nil {
                break
            } else {
                medal = append(medal, MedalNum{name:nameI, gold:goldI, silver:sliverI, bronze:bronzeI})
            }
    
            i++
        }
    
        sort.Sort(medal)
    
        for _, m := range medal {
            fmt.Println(m.name)
        }
    
    }
    

    Compare是字符串比较函数,函数原型如下所示:

    // Compare returns an integer comparing two strings lexicographically.
    // The result will be 0 if a==b, -1 if a < b, and +1 if a > b.
    func Compare(a, b string) int {
        if a == b {
            return 0
        }
        if a < b {
            return -1
        }
        return +1
    }
    

    个人主页:

    www.codeapes.cn

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