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Swift实现IOS界面的跳转

Swift实现IOS界面的跳转

作者: 小緈福 | 来源:发表于2018-07-12 11:03 被阅读0次

    IOS开发中界面跳转有两种方式,上下跳转和左右跳转。

    上下跳转_TO:

    let secondViewController = SecondViewController()

    self.presentViewController(secondViewController, animated:true, completion:nil)

    上下跳转_BACK:

    dismissViewControllerAnimated(true, completion:nil)

    -----------------------------------------------

    -----------------------------------------------

    左右跳转_TO:

    (将新的视图控制器PUSH到navigationController中,相当于入栈操作)

    let secondViewController = SecondViewController()

    self.navigationController!.pushViewController(secondViewController, animated:true)

    左右跳转_BACK:

    (将当前视图控制器从导航视图控制器堆栈中移除,从而返回到了上一级界面)

    ( - ) BACK_到上一级:

    let firstViewController = FirstViewController()

    self.navigationController?.popViewControllerAnimated(true)

    ( - ) BACK_指定界面:

    // 获得视图控制器中的某一视图控制器

    let viewController =self.navigationController?.viewControllers[0]

    self.navigationController?.popToViewController(viewController as!UIViewController, animated:true)

    ( - ) BACK_根视图:

    self.navigationController?.popToRootViewControllerAnimated(true)

    根视图的设置需要在AppDelegate中设置:

    var window:UIWindow?

    func application(application:UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool

    {

        var firstViewController = FirstViewController()

    var rootNavigationViewController =UINavigationController(rootViewController: firstViewController)

    self.window!.rootViewController = rootNavigationViewController

    returntrue

    }

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