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Swift实现IOS界面的跳转

Swift实现IOS界面的跳转

作者: 小緈福 | 来源:发表于2018-07-12 11:03 被阅读0次

IOS开发中界面跳转有两种方式,上下跳转和左右跳转。

上下跳转_TO:

let secondViewController = SecondViewController()

self.presentViewController(secondViewController, animated:true, completion:nil)

上下跳转_BACK:

dismissViewControllerAnimated(true, completion:nil)

-----------------------------------------------

-----------------------------------------------

左右跳转_TO:

(将新的视图控制器PUSH到navigationController中,相当于入栈操作)

let secondViewController = SecondViewController()

self.navigationController!.pushViewController(secondViewController, animated:true)

左右跳转_BACK:

(将当前视图控制器从导航视图控制器堆栈中移除,从而返回到了上一级界面)

( - ) BACK_到上一级:

let firstViewController = FirstViewController()

self.navigationController?.popViewControllerAnimated(true)

( - ) BACK_指定界面:

// 获得视图控制器中的某一视图控制器

let viewController =self.navigationController?.viewControllers[0]

self.navigationController?.popToViewController(viewController as!UIViewController, animated:true)

( - ) BACK_根视图:

self.navigationController?.popToRootViewControllerAnimated(true)

根视图的设置需要在AppDelegate中设置:

var window:UIWindow?

func application(application:UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool

{

    var firstViewController = FirstViewController()

var rootNavigationViewController =UINavigationController(rootViewController: firstViewController)

self.window!.rootViewController = rootNavigationViewController

returntrue

}

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