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JSONEncoder 基础类型编码失败的解决方法

JSONEncoder 基础类型编码失败的解决方法

作者: 韦弦Zhy | 来源:发表于2021-11-19 18:32 被阅读0次

    JSONEncoder 在 Swift 中还是非常常用的,最近项目中有需要将APP数据转换为JSON格式之后,再发送给服务器的需求,测试过程中,然后报了如下错误:

    invalidValue(Optional(1), 
    Swift.EncodingError.Context(codingPath: [], debugDescription: "Top-level Optional<Int> encoded as number JSON fragment.", underlyingError: nil))
    

    移除业务逻辑的话,代码大概长这样:

    class ViewController: UIViewController {
    
        struct User: Codable {
            var name: String
            var age: Int
        }
    
        override func viewDidLoad() {
            super.viewDidLoad()
            self.view.backgroundColor = .red
            // Do any additional setup after loading the view.
            sendData(1, res: nil)
            sendData(User(name: "韦弦zhy", age: 18), res: nil)
        }
    
        func sendData<T: Codable>(_ model: T?, res: ((_ error: Error?) -> Void)?) {
            guard let json = model.json() else {
                print("json error ")
                return
            }
            
            print("encoded json: \(json)")
            // begin send data
            // res?(error)
        }
    }
    
    extension Encodable {
        /// 将model转换为json
        /// - Returns: json?
        func json() -> String? {
            var modelJson: String? = nil
            do {
                let data = try JSONEncoder().encode(self)
                modelJson = String(data: data, encoding: .utf8)
            } catch {
                print(error)
            }
            return modelJson
        }
    }
    

    最初开发的时候一切都很正常,不管我传递的 model1 还是 "1" 或者是 一个 User, 代码跑起来打印如下:

    encoded json: 1
    encoded json: {"name":"韦弦zhy","age":18}
    
    问题开始

    当开始兼容性测试时,iOS 13 系统以下,业务突然完全无法实现,查看 log:

    invalidValue(Optional(1), Swift.EncodingError.Context(codingPath: [], debugDescription: "Top-level Optional<Int> encoded as number JSON fragment.", underlyingError: nil))
    
    json error 
    
    encoded json: {"name":"韦弦zhy","age":18}
    

    后续测试发现:只有类似 User 这样的结构体或类才能正常编码,而基础类型 Int , Double, String 等,均无法编码成功,可是查看encode 接口并没有相关描述:

    open class JSONEncoder {
        ...
    
        /// Encodes the given top-level value and returns its JSON representation.
        ///
        /// - parameter value: The value to encode.
        /// - returns: A new `Data` value containing the encoded JSON data.
        /// - throws: `EncodingError.invalidValue` if a non-conforming floating-point value is encountered during encoding, and the encoding strategy is `.throw`.
        /// - throws: An error if any value throws an error during encoding.
        open func encode<T>(_ value: T) throws -> Data where T : Encodable
    }
    

    在 Swift JSONEncoder 的源码中也翻了翻,也是没找到关于iOS 版本相关描述,方法实现如下:

    open class JSONEncoder {
        ...
    
        /// Encodes the given top-level value and returns its JSON representation.
        ///
        /// - parameter value: The value to encode.
        /// - returns: A new `Data` value containing the encoded JSON data.
        /// - throws: `EncodingError.invalidValue` if a non-conforming floating-point value is encountered during encoding, and the encoding strategy is `.throw`.
        /// - throws: An error if any value throws an error during encoding.
        open func encode<T : Encodable>(_ value: T) throws -> Data {
            let encoder = _JSONEncoder(options: self.options)
    
            guard let topLevel = try encoder.box_(value) else {
                throw EncodingError.invalidValue(value, EncodingError.Context(codingPath: [], debugDescription: "Top-level \(T.self) did not encode any values."))
            }
    
            if topLevel is NSNull {
                throw EncodingError.invalidValue(value, EncodingError.Context(codingPath: [], debugDescription: "Top-level \(T.self) encoded as null JSON fragment."))
            } else if topLevel is NSNumber {
                throw EncodingError.invalidValue(value, EncodingError.Context(codingPath: [], debugDescription: "Top-level \(T.self) encoded as number JSON fragment."))
            } else if topLevel is NSString {
                throw EncodingError.invalidValue(value, EncodingError.Context(codingPath: [], debugDescription: "Top-level \(T.self) encoded as string JSON fragment."))
            }
    
            let writingOptions = JSONSerialization.WritingOptions(rawValue: self.outputFormatting.rawValue)
            do {
               return try JSONSerialization.data(withJSONObject: topLevel, options: writingOptions)
            } catch {
                throw EncodingError.invalidValue(value, EncodingError.Context(codingPath: [], debugDescription: "Unable to encode the given top-level value to JSON.", underlyingError: error))
            }
        }
    }
    

    内部实现会先调用 box_方法封装,得到topLevel, 实际上 box_ 内部主要又是调用 box 方法将基础类型转换为NSStringNSNumber(这里只关注基础类型,其他的可以自行查看源码) 所以才有了encode 中的判断 NSNumberNSString 然后抛出异常。。。

    问题来了。。。iOS 13 之后怎么就可以了,没找到代码。。。有人找到望同步一下

    最终,为了代码能够正常运行,改了一下扩展方法, 经过测试,已经可以表现正常,因为不知道具体生效的版本(万一是12.x呢),所以判断写在了抛出异常的地方,否则可以写在encode之前:

    extension Encodable {
        /// 将model转换为json
        /// - Returns: json?
        func json() -> String? {
            var modelJson: String? = nil
            do {
                let data = try JSONEncoder().encode(self)
                modelJson = String(data: data, encoding: .utf8)
            } catch {
                /// see: https://github.com/apple/swift/blob/56a1663c9859f1283904cb0be4774a4e79d60a22/stdlib/public/SDK/Foundation/JSONEncoder.swift
                /// 从源码也找不到具体是从哪个版本才支持对 Int Double String 等基本类型的的支持
                if (self is NSNumber) || (self is NSString) {
                    return "\(self)"
                }
                
                print(error)
            }
            return modelJson
        }
    }
    

    问题是解决了,可是,原因还是没找到。。。。

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