Leetcode 210. Course Schedule II

作者: ShutLove | 来源:发表于2017-11-24 16:59 被阅读5次

    There are a total of n courses you have to take, labeled from 0 to n - 1.
    Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1]
    Given the total number of courses and a list of prerequisite pairs, return the ordering of courses you should take to finish all courses.
    There may be multiple correct orders, you just need to return one of them. If it is impossible to finish all courses, return an empty array.

    For example:
    2, [[1,0]]
    There are a total of 2 courses to take. To take course 1 you should have finished course 0. So the correct course order is [0,1]
    4, [[1,0],[2,0],[3,1],[3,2]]
    There are a total of 4 courses to take. To take course 3 you should have finished both courses 1 and 2. Both courses 1 and 2 should be taken after you finished course 0. So one correct course order is [0,1,2,3]. Another correct ordering is[0,2,1,3].

    思路:
    基本同207题是一样的,只是要求返回的结果不同,参见207.

    public int[] findOrder(int numCourses, int[][] prerequisites) {
        //tip 后面的是前置条件
        int[] preCount = new int[numCourses];
        List<List<Integer>> unlock = new ArrayList<>();
        for (int i = 0; i < numCourses; i++) {
            unlock.add(new ArrayList<>());
        }
    
        for (int i = 0; i < prerequisites.length; i++) {
            int[] pre = prerequisites[i];
            preCount[pre[0]] += 1;
            unlock.get(pre[1]).add(pre[0]);
        }
    
        //use queue to search and count
        int cnt = 0;
        Queue<Integer> q = new LinkedList<>();
        for (int i = 0; i < numCourses; i++) {
            if (preCount[i] == 0) {
                q.offer(i);
            }
        }
        int[] res = new int[numCourses];
        while (!q.isEmpty()) {
            int num = q.poll();
            res[cnt] = num;
            cnt++;
            List<Integer> subs = unlock.get(num);
            for (int i = 0; i < subs.size(); i++) {
                int next = subs.get(i);
                preCount[next] -= 1;
                if (preCount[next] == 0) {
                    q.offer(next);
                }
            }
        }
    
        return cnt == numCourses ? res : new int[0];
    }

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