美文网首页python实现deep learningPython之旅python
21天pandas入门手册(1) - 10分钟入门1

21天pandas入门手册(1) - 10分钟入门1

作者: default | 来源:发表于2016-03-14 12:15 被阅读13353次

    这个是根据pandas官网文档翻译出来,文档里面是包含一切,这里只是记录一下实际会用到的东西。
    比如selection可能有好几种方法,记录一种就可以了。
    版本是0.18.0

    # pandas里面竟然有个panel,3d数据,不过一般用不到
    

    10分钟入门 - 一个简单的介绍


    习惯上,像这样import:

    In [1]: import pandas as pd
    In [2]: import numpy as np
    In [3]: import matplotlib.pyplot as plt
    

    对象的创建

    详细在这里
    创建一个Series,可以通过传入一个value的list,让pandas创建一个默认的整数index

    In [4]: s = pd.Series([1,3,5,np.nan,6,8])
    In [5]: s
    Out[5]: 
    0 1
    1 3
    2 5
    3 NaN
    4 6
    5 8
    dtype: float64
    

    创建一个DataFrame,通过传入一个numpy的二维数组,一个datetime的index,和一个列名。

    In [6]: dates = pd.date_range('20130101', periods=6)
    In [7]: dates
    Out[7]: 
    DatetimeIndex(['2013-01-01', '2013-01-02', '2013-01-03', '2013-01-04',
               '2013-01-05', '2013-01-06'],
              dtype='datetime64[ns]', freq='D')
    
    In [8]: df = pd.DataFrame(np.random.randn(6,4), index=dates, columns=list('ABCD'))
    
    In [9]: df
    Out[9]: 
                   A         B         C         D
    2013-01-01  0.469112 -0.282863 -1.509059 -1.135632
    2013-01-02  1.212112 -0.173215  0.119209 -1.044236
    2013-01-03 -0.861849 -2.104569 -0.494929  1.071804
    2013-01-04  0.721555 -0.706771 -1.039575  0.271860
    2013-01-05 -0.424972  0.567020  0.276232 -1.087401
    2013-01-06 -0.673690  0.113648 -1.478427  0.524988
    

    创建一个DataFrame,通过传入一个字典,字典的object可以转换成Series-like。

    In [10]: df2 = pd.DataFrame({ 'A' : 1.,
       ....:                      'B' : pd.Timestamp('20130102'),
       ....:                      'C' : pd.Series(1,index=list(range(4)),dtype='float32'),
       ....:                      'D' : np.array([3] * 4,dtype='int32'),
       ....:                      'E' : pd.Categorical(["test","train","test","train"]),
       ....:                      'F' : 'foo' })
       ....: 
    
    In [11]: df2
    Out[11]: 
       A          B  C  D      E    F
    0  1 2013-01-02  1  3   test  foo
    1  1 2013-01-02  1  3  train  foo
    2  1 2013-01-02  1  3   test  foo
    3  1 2013-01-02  1  3  train  foo
    

    有不同的dtypes

    In [12]: df2.dtypes
    Out[12]: 
    A           float64
    B    datetime64[ns]
    C           float32
    D             int32
    E          category
    F            object
    dtype: object
    

    查看数据

    看这里
    看一个frame的top和bottom的几行

    In [14]: df.head()
    Out[14]: 
                       A         B         C         D
    2013-01-01  0.469112 -0.282863 -1.509059 -1.135632
    2013-01-02  1.212112 -0.173215  0.119209 -1.044236
    2013-01-03 -0.861849 -2.104569 -0.494929  1.071804
    2013-01-04  0.721555 -0.706771 -1.039575  0.271860
    2013-01-05 -0.424972  0.567020  0.276232 -1.087401
    
    In [15]: df.tail(3)
    Out[15]: 
                   A         B         C         D
    2013-01-04  0.721555 -0.706771 -1.039575  0.271860
    2013-01-05 -0.424972  0.567020  0.276232 -1.087401
    2013-01-06 -0.673690  0.113648 -1.478427  0.524988
    

    看一下index,column,以及背后的numpy

    In [16]: df.index
    Out[16]: 
    DatetimeIndex(['2013-01-01', '2013-01-02', '2013-01-03', '2013-01-04',
               '2013-01-05', '2013-01-06'],
              dtype='datetime64[ns]', freq='D')
    
    In [17]: df.columns
    Out[17]: Index([u'A', u'B', u'C', u'D'], dtype='object')
    
    In [18]: df.values
    Out[18]: 
    array([[ 0.4691, -0.2829, -1.5091, -1.1356],
       [ 1.2121, -0.1732,  0.1192, -1.0442],
       [-0.8618, -2.1046, -0.4949,  1.0718],
       [ 0.7216, -0.7068, -1.0396,  0.2719],
       [-0.425 ,  0.567 ,  0.2762, -1.0874],
       [-0.6737,  0.1136, -1.4784,  0.525 ]])
    

    看一下统计数据

    In [19]: df.describe()
    Out[19]: 
              A         B         C         D
    count  6.000000  6.000000  6.000000  6.000000
    mean   0.073711 -0.431125 -0.687758 -0.233103
    std    0.843157  0.922818  0.779887  0.973118
    min   -0.861849 -2.104569 -1.509059 -1.135632
    25%   -0.611510 -0.600794 -1.368714 -1.076610
    50%    0.022070 -0.228039 -0.767252 -0.386188
    75%    0.658444  0.041933 -0.034326  0.461706
    max    1.212112  0.567020  0.276232  1.071804
    

    转置:

    In [20]: df.T
    Out[20]: 
       2013-01-01  2013-01-02  2013-01-03  2013-01-04  2013-01-05  2013-01-06
    A    0.469112    1.212112   -0.861849    0.721555   -0.424972   -0.673690
    B   -0.282863   -0.173215   -2.104569   -0.706771    0.567020    0.113648
    C   -1.509059    0.119209   -0.494929   -1.039575    0.276232   -1.478427
    D   -1.135632   -1.044236    1.071804    0.271860   -1.087401    0.524988
    

    排序,按照axis

    In [21]: df.sort_index(axis=1, ascending=False) # 像是column
    Out[21]: 
                       D         C         B         A
    2013-01-01 -1.135632 -1.509059 -0.282863  0.469112
    2013-01-02 -1.044236  0.119209 -0.173215  1.212112
    2013-01-03  1.071804 -0.494929 -2.104569 -0.861849
    2013-01-04  0.271860 -1.039575 -0.706771  0.721555
    2013-01-05 -1.087401  0.276232  0.567020 -0.424972
    2013-01-06  0.524988 -1.478427  0.113648 -0.673690
    

    按照value排序

    In [22]: df.sort_values(by='B')
    Out[22]: 
                       A         B         C         D
    2013-01-03 -0.861849 -2.104569 -0.494929  1.071804
    2013-01-04  0.721555 -0.706771 -1.039575  0.271860
    2013-01-01  0.469112 -0.282863 -1.509059 -1.135632
    2013-01-02  1.212112 -0.173215  0.119209 -1.044236
    2013-01-06 -0.673690  0.113648 -1.478427  0.524988
    2013-01-05 -0.424972  0.567020  0.276232 -1.087401
    

    selection

    虽然说标准python和numpy的selection都非常直接间接,但是对于工业环境,还是推荐通过函数来访问数据 at, iat, loc, iloc,ix

    索引看这里
    还有这里

    获得一列,返回值是一个Series,和df.A是等价的

    In [23]: df['A']
    Out[23]: 
    2013-01-01    0.469112
    2013-01-02    1.212112
    2013-01-03   -0.861849
    2013-01-04    0.721555
    2013-01-05   -0.424972
    2013-01-06   -0.673690
    Freq: D, Name: A, dtype: float64
    

    通过[],会对进行切片, 是行行行行行行行行行行行行行行行行行行行

    In [24]: df[0:3]
    Out[24]: 
                   A         B         C         D
    2013-01-01  0.469112 -0.282863 -1.509059 -1.135632
    2013-01-02  1.212112 -0.173215  0.119209 -1.044236
    2013-01-03 -0.861849 -2.104569 -0.494929  1.071804
    
    In [25]: df['20130102':'20130104']
    Out[25]: 
                       A         B         C         D
    2013-01-02  1.212112 -0.173215  0.119209 -1.044236
    2013-01-03 -0.861849 -2.104569 -0.494929  1.071804
    2013-01-04  0.721555 -0.706771 -1.039575  0.271860
    

    获取一个cross,就是一个十字吧

    In [26]: df.loc[dates[0]]
    Out[26]: 
    A    0.469112
    B   -0.282863
    C   -1.509059
    D   -1.135632
    Name: 2013-01-01 00:00:00, dtype: float64
    

    获取一个正方形

    In [27]: df.loc[:,['A','B']]
    Out[27]: 
                   A         B
    2013-01-01  0.469112 -0.282863
    2013-01-02  1.212112 -0.173215
    2013-01-03 -0.861849 -2.104569
    2013-01-04  0.721555 -0.706771
    2013-01-05 -0.424972  0.567020
    2013-01-06 -0.673690  0.113648
    
    In [28]: df.loc['20130102':'20130104',['A','B']]
    Out[28]: 
                   A         B
    2013-01-02  1.212112 -0.173215
    2013-01-03 -0.861849 -2.104569
    2013-01-04  0.721555 -0.706771
    
    In [29]: df.loc['20130102',['A','B']]
    Out[29]: 
    A    1.212112
    B   -0.173215
    Name: 2013-01-02 00:00:00, dtype: float64
    

    获取一个元素

    In [30]: df.loc[dates[0],'A']
    Out[30]: 0.46911229990718628
    In [31]: df.at[dates[0],'A']
    Out[31]: 0.46911229990718628
    

    通过位置selection
    详细看这里

    In [32]: df.iloc[3]
    Out[32]: 
    A    0.721555
    B   -0.706771
    C   -1.039575
    D    0.271860
    Name: 2013-01-04 00:00:00, dtype: float64
    
    In [33]: df.iloc[3:5,0:2]
    Out[33]: 
                   A         B
    2013-01-04  0.721555 -0.706771
    2013-01-05 -0.424972  0.567020
    
    In [34]: df.iloc[[1,2,4],[0,2]]
    Out[34]: 
                   A         C
    2013-01-02  1.212112  0.119209
    2013-01-03 -0.861849 -0.494929
    2013-01-05 -0.424972  0.276232
    
    In [35]: df.iloc[1:3,:]
    Out[35]: 
                   A         B         C         D
    2013-01-02  1.212112 -0.173215  0.119209 -1.044236
    2013-01-03 -0.861849 -2.104569 -0.494929  1.071804
    

    得到一个元素,可以通过iloc,但是更快的方法是iat

    In [37]: df.iloc[1,1]
    Out[37]: -0.17321464905330858
    In [38]: df.iat[1,1]
    Out[38]: -0.17321464905330858
    

    boolean索引
    可以通过某一行的值来选择数据

    In [39]: df[df.A > 0]
    Out[39]: 
                   A         B         C         D
    2013-01-01  0.469112 -0.282863 -1.509059 -1.135632
    2013-01-02  1.212112 -0.173215  0.119209 -1.044236
    2013-01-04  0.721555 -0.706771 -1.039575  0.271860
    

    或者类似where:

    In [40]: df[df > 0]
    Out[40]: 
                   A         B         C         D
    2013-01-01  0.469112       NaN       NaN       NaN
    2013-01-02  1.212112       NaN  0.119209       NaN
    2013-01-03       NaN       NaN       NaN  1.071804
    2013-01-04  0.721555       NaN       NaN  0.271860
    2013-01-05       NaN  0.567020  0.276232       NaN
    2013-01-06       NaN  0.113648       NaN  0.524988
    

    使用isin

    In [41]: df2 = df.copy()
    
    In [42]: df2['E'] = ['one', 'one','two','three','four','three']
    
    In [43]: df2
    Out[43]: 
                   A         B         C         D      E
    2013-01-01  0.469112 -0.282863 -1.509059 -1.135632    one
    2013-01-02  1.212112 -0.173215  0.119209 -1.044236    one
    2013-01-03 -0.861849 -2.104569 -0.494929  1.071804    two
    2013-01-04  0.721555 -0.706771 -1.039575  0.271860  three
    2013-01-05 -0.424972  0.567020  0.276232 -1.087401   four
    2013-01-06 -0.673690  0.113648 -1.478427  0.524988  three
    
    In [44]: df2[df2['E'].isin(['two','four'])]
    Out[44]: 
                   A         B         C         D     E
    2013-01-03 -0.861849 -2.104569 -0.494929  1.071804   two
    2013-01-05 -0.424972  0.567020  0.276232 -1.087401  four
    

    赋值:

    In [45]: s1 = pd.Series([1,2,3,4,5,6], index=pd.date_range('20130102', periods=6))
    
    In [46]: s1
    Out[46]: 
    2013-01-02    1
    2013-01-03    2
    2013-01-04    3
    2013-01-05    4
    2013-01-06    5
    2013-01-07    6
    Freq: D, dtype: int64
    
    In [47]: df['F'] = s1
    
    In [48]: df.at[dates[0],'A'] = 0
    In [49]: df.iat[0,1] = 0
    In [50]: df.loc[:,'D'] = np.array([5] * len(df))
    
    In [51]: df
    Out[51]: 
                   A         B         C  D   F
    2013-01-01  0.000000  0.000000 -1.509059  5 NaN
    2013-01-02  1.212112 -0.173215  0.119209  5   1
    2013-01-03 -0.861849 -2.104569 -0.494929  5   2
    2013-01-04  0.721555 -0.706771 -1.039575  5   3
    2013-01-05 -0.424972  0.567020  0.276232  5   4
    2013-01-06 -0.673690  0.113648 -1.478427  5   5
    

    where操作来赋值

    In [52]: df2 = df.copy()
    In [53]: df2[df2 > 0] = -df2
    In [54]: df2
    Out[54]: 
                   A         B         C  D   F
    2013-01-01  0.000000  0.000000 -1.509059 -5 NaN
    2013-01-02 -1.212112 -0.173215 -0.119209 -5  -1
    2013-01-03 -0.861849 -2.104569 -0.494929 -5  -2
    2013-01-04 -0.721555 -0.706771 -1.039575 -5  -3
    2013-01-05 -0.424972 -0.567020 -0.276232 -5  -4
    2013-01-06 -0.673690 -0.113648 -1.478427 -5  -5
    

    missing data:
    pandas使用np.nan来表示missing data。默认是不参与计算的。

    In [55]: df1 = df.reindex(index=dates[0:4], columns=list(df.columns) + ['E'])
    
    In [56]: df1.loc[dates[0]:dates[1],'E'] = 1
    
    In [57]: df1
    Out[57]: 
                   A         B         C  D   F   E
    2013-01-01  0.000000  0.000000 -1.509059  5 NaN   1
    2013-01-02  1.212112 -0.173215  0.119209  5   1   1
    2013-01-03 -0.861849 -2.104569 -0.494929  5   2 NaN
    2013-01-04  0.721555 -0.706771 -1.039575  5   3 NaN
    

    drop掉包含nan的行
    In [58]: df1.dropna(how='any')
    Out[58]:
    A B C D F E
    2013-01-02 1.212112 -0.173215 0.119209 5 1 1
    fill missing data:

    In [59]: df1.fillna(value=5)
    Out[59]: 
                   A         B         C  D  F  E
    2013-01-01  0.000000  0.000000 -1.509059  5  5  1
    2013-01-02  1.212112 -0.173215  0.119209  5  1  1
    2013-01-03 -0.861849 -2.104569 -0.494929  5  2  5
    2013-01-04  0.721555 -0.706771 -1.039575  5  3  5
    

    获取一个boolean的mask

    In [60]: pd.isnull(df1)
    Out[60]: 
                A      B      C      D      F      E
    2013-01-01  False  False  False  False   True  False
    2013-01-02  False  False  False  False  False  False
    2013-01-03  False  False  False  False  False   True
    2013-01-04  False  False  False  False  False   True
    

    操作,计算

    二元操作看这里
    统计:

    In [61]: df.mean()
    Out[61]: 
    A   -0.004474
    B   -0.383981
    C   -0.687758
    D    5.000000
    F    3.000000
    dtype: float64
    

    另一个维度的统计

    In [62]: df.mean(1)
    Out[62]: 
    2013-01-01    0.872735
    2013-01-02    1.431621
    2013-01-03    0.707731
    2013-01-04    1.395042
    2013-01-05    1.883656
    2013-01-06    1.592306
    Freq: D, dtype: float64
    

    对不同维度操作需要对比,pandas会在对应维度上broadcasting

    In [63]: s = pd.Series([1,3,5,np.nan,6,8], index=dates).shift(2)
    
    In [64]: s
    Out[64]: 
    2013-01-01   NaN
    2013-01-02   NaN
    2013-01-03     1
    2013-01-04     3
    2013-01-05     5
    2013-01-06   NaN
    Freq: D, dtype: float64
    
    In [65]: df.sub(s, axis='index')
    Out[65]: 
                   A         B         C   D   F
    2013-01-01       NaN       NaN       NaN NaN NaN
    2013-01-02       NaN       NaN       NaN NaN NaN
    2013-01-03 -1.861849 -3.104569 -1.494929   4   1
    2013-01-04 -2.278445 -3.706771 -4.039575   2   0
    2013-01-05 -5.424972 -4.432980 -4.723768   0  -1
    2013-01-06       NaN       NaN       NaN NaN NaN
    

    apply :(这怎么翻译)

    In [66]: df.apply(np.cumsum)
    Out[66]: 
                   A         B         C   D   F
    2013-01-01  0.000000  0.000000 -1.509059   5 NaN
    2013-01-02  1.212112 -0.173215 -1.389850  10   1
    2013-01-03  0.350263 -2.277784 -1.884779  15   3
    2013-01-04  1.071818 -2.984555 -2.924354  20   6
    2013-01-05  0.646846 -2.417535 -2.648122  25  10
    2013-01-06 -0.026844 -2.303886 -4.126549  30  15
    
    In [67]: df.apply(lambda x: x.max() - x.min())
    Out[67]: 
    A    2.073961
    B    2.671590
    C    1.785291
    D    0.000000
    F    4.000000
    dtype: float64
    

    直方图和离散化(Histogramming and Discretization

    In [68]: s = pd.Series(np.random.randint(0, 7, size=10))
    
    In [69]: s
    Out[69]: 
    0    4
    1    2
    2    1
    3    2
    4    6
    5    4
    6    4
    7    6
    8    4
    9    4
    dtype: int32
    
    In [70]: s.value_counts()
    Out[70]: 
    4    5
    6    2
    2    2
    1    1
    dtype: int64
    

    字符串操作
    Note that pattern-matching in str generally uses regular expressions by default (and in some cases always uses them). See more at Vectorized String Methods.

    In [71]: s = pd.Series(['A', 'B', 'C', 'Aaba', 'Baca', np.nan, 'CABA', 'dog', 'cat'])
    
    In [72]: s.str.lower()
    Out[72]: 
    0       a
    1       b
    2       c
    3    aaba
    4    baca
    5     NaN
    6    caba
    7     dog
    8     cat
    dtype: object
    

    merge

    相关文章

      网友评论

      本文标题:21天pandas入门手册(1) - 10分钟入门1

      本文链接:https://www.haomeiwen.com/subject/upjflttx.html