备注:测试数据库版本为MySQL 8.0
如需要scott用户下建表及录入数据语句,可参考:
scott建表及录入数据sql脚本
一.需求
正在执行一个group by查询,并希望返回哪些属于选择列表而不包含于group by子句的列。
通常,这是不可能的,因为对于这样的非组列,并不时每行都包含唯一值。
假设要找到每个部门中工资最高和最低的员工,以及每种职位中工资最高和最低的员工,要查看这些人的姓名、所在部门、职位名称以及工资。
希望返回的结果集如下:
+--------+--------+-----------+---------+-----------------+----------------+
| deptno | ename | job | sal | dept_status | job_status |
+--------+--------+-----------+---------+-----------------+----------------+
| 20 | SCOTT | ANALYST | 3000.00 | TOP SAL IN DEPT | TOP SAL IN JOB |
| 20 | FORD | ANALYST | 3000.00 | TOP SAL IN DEPT | TOP SAL IN JOB |
| 10 | MILLER | CLERK | 1300.00 | LOW SAL IN DEPT | TOP SAL IN JOB |
| 20 | SMITH | CLERK | 800.00 | LOW SAL IN DEPT | LOW SAL IN JOB |
| 30 | JAMES | CLERK | 950.00 | LOW SAL IN DEPT | NULL |
| 10 | CLARK | MANAGER | 2450.00 | NULL | LOW SAL IN JOB |
| 20 | JONES | MANAGER | 2975.00 | NULL | TOP SAL IN JOB |
| 30 | BLAKE | MANAGER | 2850.00 | TOP SAL IN DEPT | NULL |
| 10 | KING | PRESIDENT | 5000.00 | TOP SAL IN DEPT | TOP SAL IN JOB |
| 30 | ALLEN | SALESMAN | 1600.00 | NULL | TOP SAL IN JOB |
| 30 | WARD | SALESMAN | 1250.00 | NULL | LOW SAL IN JOB |
| 30 | MARTIN | SALESMAN | 1250.00 | NULL | LOW SAL IN JOB |
+--------+--------+-----------+---------+-----------------+----------------+
二.解决方案
使用内敛视图,按deptno和job找到最高工资和最低工资。然后,只保留工资最高或工资最低的员工。
2.1 子查询方法
select deptno,ename,job,sal,
case when sal = max_by_dept
then 'TOP SAL IN DEPT'
when sal = min_by_dept
then 'LOW SAL IN DEPT'
end as dept_status,
case when sal = max_by_job
then 'TOP SAL IN JOB'
when sal = min_by_job
then 'LOW SAL IN JOB'
end as job_status
from (
select e.deptno,e.ename,e.job,e.sal,
(select max(sal) from emp d
where d.deptno = e.deptno) as max_by_dept,
(select max(sal) from emp d
where d.job = e.job) as max_by_job,
(select min(sal) from emp d
where d.deptno = e.deptno) as min_by_dept,
(select min(sal) from emp d
where d.job = e.job) as min_by_job
from emp e
) x
where sal in (max_by_dept,max_by_job,
min_by_dept,min_by_job);
测试记录:
mysql> select deptno,ename,job,sal,
-> case when sal = max_by_dept
-> then 'TOP SAL IN DEPT'
-> when sal = min_by_dept
-> then 'LOW SAL IN DEPT'
-> end as dept_status,
-> case when sal = max_by_job
-> then 'TOP SAL IN JOB'
-> when sal = min_by_job
-> then 'LOW SAL IN JOB'
-> end as job_status
-> from (
-> select e.deptno,e.ename,e.job,e.sal,
-> (select max(sal) from emp d
-> where d.deptno = e.deptno) as max_by_dept,
-> (select max(sal) from emp d
-> where d.job = e.job) as max_by_job,
-> (select min(sal) from emp d
-> where d.deptno = e.deptno) as min_by_dept,
-> (select min(sal) from emp d
-> where d.job = e.job) as min_by_job
-> from emp e
-> ) x
-> where sal in (max_by_dept,max_by_job,
-> min_by_dept,min_by_job);
+--------+--------+-----------+---------+-----------------+----------------+
| deptno | ename | job | sal | dept_status | job_status |
+--------+--------+-----------+---------+-----------------+----------------+
| 20 | SMITH | CLERK | 800.00 | LOW SAL IN DEPT | LOW SAL IN JOB |
| 30 | ALLEN | SALESMAN | 1600.00 | NULL | TOP SAL IN JOB |
| 30 | WARD | SALESMAN | 1250.00 | NULL | LOW SAL IN JOB |
| 20 | JONES | MANAGER | 2975.00 | NULL | TOP SAL IN JOB |
| 30 | MARTIN | SALESMAN | 1250.00 | NULL | LOW SAL IN JOB |
| 30 | BLAKE | MANAGER | 2850.00 | TOP SAL IN DEPT | NULL |
| 10 | CLARK | MANAGER | 2450.00 | NULL | LOW SAL IN JOB |
| 20 | SCOTT | ANALYST | 3000.00 | TOP SAL IN DEPT | TOP SAL IN JOB |
| 10 | KING | PRESIDENT | 5000.00 | TOP SAL IN DEPT | TOP SAL IN JOB |
| 30 | JAMES | CLERK | 950.00 | LOW SAL IN DEPT | NULL |
| 20 | FORD | ANALYST | 3000.00 | TOP SAL IN DEPT | TOP SAL IN JOB |
| 10 | MILLER | CLERK | 1300.00 | LOW SAL IN DEPT | TOP SAL IN JOB |
+--------+--------+-----------+---------+-----------------+----------------+
12 rows in set (0.00 sec)
2.2 MySQL 8.0 窗口函数方法
select deptno,ename,job,sal,
case when sal = max_by_dept
then 'TOP SAL IN DEPT'
when sal = min_by_dept
then 'LOW SAL IN DEPT'
end as dept_status,
case when sal = max_by_job
then 'TOP SAL IN JOB'
when sal = min_by_job
then 'LOW SAL IN JOB'
end as job_status
from (
select deptno,ename,job,sal,
max(sal) over w1 as 'max_by_dept',
max(sal) over w2 as 'max_by_job',
min(sal) over w1 as 'min_by_dept',
min(sal) over w2 as 'min_by_job'
from emp
window w1 as (partition by deptno),
w2 as (partition by job)
) x
where sal in (max_by_dept,max_by_job,
min_by_dept,min_by_job);
测试记录:
mysql> select deptno,ename,job,sal,
-> case when sal = max_by_dept
-> then 'TOP SAL IN DEPT'
-> when sal = min_by_dept
-> then 'LOW SAL IN DEPT'
-> end as dept_status,
-> case when sal = max_by_job
-> then 'TOP SAL IN JOB'
-> when sal = min_by_job
-> then 'LOW SAL IN JOB'
-> end as job_status
-> from (
-> select deptno,ename,job,sal,
-> max(sal) over w1 as 'max_by_dept',
-> max(sal) over w2 as 'max_by_job',
-> min(sal) over w1 as 'min_by_dept',
-> min(sal) over w2 as 'min_by_job'
-> from emp
-> window w1 as (partition by deptno),
-> w2 as (partition by job)
-> ) x
-> where sal in (max_by_dept,max_by_job,
-> min_by_dept,min_by_job);
+--------+--------+-----------+---------+-----------------+----------------+
| deptno | ename | job | sal | dept_status | job_status |
+--------+--------+-----------+---------+-----------------+----------------+
| 20 | SCOTT | ANALYST | 3000.00 | TOP SAL IN DEPT | TOP SAL IN JOB |
| 20 | FORD | ANALYST | 3000.00 | TOP SAL IN DEPT | TOP SAL IN JOB |
| 10 | MILLER | CLERK | 1300.00 | LOW SAL IN DEPT | TOP SAL IN JOB |
| 20 | SMITH | CLERK | 800.00 | LOW SAL IN DEPT | LOW SAL IN JOB |
| 30 | JAMES | CLERK | 950.00 | LOW SAL IN DEPT | NULL |
| 10 | CLARK | MANAGER | 2450.00 | NULL | LOW SAL IN JOB |
| 20 | JONES | MANAGER | 2975.00 | NULL | TOP SAL IN JOB |
| 30 | BLAKE | MANAGER | 2850.00 | TOP SAL IN DEPT | NULL |
| 10 | KING | PRESIDENT | 5000.00 | TOP SAL IN DEPT | TOP SAL IN JOB |
| 30 | ALLEN | SALESMAN | 1600.00 | NULL | TOP SAL IN JOB |
| 30 | WARD | SALESMAN | 1250.00 | NULL | LOW SAL IN JOB |
| 30 | MARTIN | SALESMAN | 1250.00 | NULL | LOW SAL IN JOB |
+--------+--------+-----------+---------+-----------------+----------------+
12 rows in set (0.00 sec)
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