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Xcode:脚本打包静态库

Xcode:脚本打包静态库

作者: 春暖花已开 | 来源:发表于2019-04-09 06:44 被阅读0次
    脚本
    #!/bin/sh
    #获取执行权限
    sudo xcode-select -switch /Applications/Xcode.app/Contents/Developer
    #要build的target名
    TARGET_NAME_Base=${PROJECT_NAME}
    
    if [[ $1 ]]
    then
    TARGET_NAME_Base=$1
    fi
    
    #Release
    CONFIGURATION="Release"
    #把打包好的静态库放到桌面
    UNIVERSAL_OUTPUT_FOLDER="$HOME/Desktop/${CONFIGURATION}/"
    
    #创建输出目录,并删除之前的framework文件
    mkdir -p "${UNIVERSAL_OUTPUT_FOLDER}"
    rm -rf "${UNIVERSAL_OUTPUT_FOLDER}/${TARGET_NAME_Base}.framework"
    
    #分别编译模拟器和真机的Framework   TARGET_NAME
    xcodebuild -target "${TARGET_NAME_Base}" ONLY_ACTIVE_ARCH=NO -configuration ${CONFIGURATION} -sdk iphoneos BUILD_DIR="${BUILD_DIR}" BUILD_ROOT="${BUILD_ROOT}" clean build
    xcodebuild -target "${TARGET_NAME_Base}" ONLY_ACTIVE_ARCH=NO -configuration ${CONFIGURATION} -sdk iphonesimulator BUILD_DIR="${BUILD_DIR}" BUILD_ROOT="${BUILD_ROOT}" clean build
    
    
    #拷贝framework到Debug目录
    cp -R "${BUILD_DIR}/${CONFIGURATION}-iphoneos/${TARGET_NAME_Base}.framework" "${UNIVERSAL_OUTPUT_FOLDER}"
    
    ###合并framework,输出最终的framework到Debug目录
    lipo -create "${BUILD_DIR}/${CONFIGURATION}-iphonesimulator/${TARGET_NAME_Base}.framework/${TARGET_NAME_Base}" "${UNIVERSAL_OUTPUT_FOLDER}${TARGET_NAME_Base}.framework/${TARGET_NAME_Base}" -output "${UNIVERSAL_OUTPUT_FOLDER}/${TARGET_NAME_Base}.framework/${TARGET_NAME_Base}"
    
    #删除编译之后生成的无关的配置文件
    dir_path="${UNIVERSAL_OUTPUT_FOLDER}/${TARGET_NAME_Base}.framework/"
    
    for file in ls $dir_path
    do
    if [[ ${file} =~ ".xcconfig" ]]
    then
    rm -f "${dir_path}/${file}"
    fi
    done
    
    if [ -d "${SRCROOT}/build" ]
    then
    rm -rf "${SRCROOT}/build"
    fi
    
    rm -rf "${BUILD_DIR}/${CONFIGURATION}-iphonesimulator" "${BUILD_DIR}/${CONFIGURATION}-iphoneos"
    
    open "${UNIVERSAL_OUTPUT_FOLDER}"
    

    调用:其中TestSDK为静态库的包名

    ./${PROJECT_NAME}/shell.sh TestSDK
    

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