方法1:两层for循环,外层循环原数组,内层循环时进行比较。
Array.prototype.removal = function(){
var arr = this,
result = [],
i,
j,
len = arr.length;
for(i = 0; i < len; i++){
for(j = i + 1; j < len; j++){
if(arr[i] === arr[j]){
j = ++i;
}
}
result.push(arr[i]);
}
return result;
}
var arr1 = [1,2,3,4,2,3,1,4,5,6,6];
arr1.removal();//返回[2,3,1,4,5,6]
方法2:利用对象的属性不能相同的特点去重
Array.prototype.removal = function(){
var arr = this,
i,
obj = {},
result = [],
len = arr.length;
for(i = 0; i < len; i++){
if(!obj[arr[i]]){
obj[arr[i]] = 1;
result.push(arr[i]);
}
}
return result;
}
var arr1 = [1,2,3,4,2,3,1,4,5,6,6];
arr1.removal();//返回[1,2,3,4,5,6]
方法3:利用splice直接在原数组进行操作
Array.prototype.removal = function(){
var arr = this,
i,
j,
len = arr.length;
for(i = 0; i < len; i++){
for(j = i + 1; j < len; j++){
if(arr[i] == arr[j]){
arr.splice(j,1);
len--;
j--;
}
}
}
return arr;
}
var arr1 = [1,2,3,4,2,3,1,4,5,6,6];
arr1.removal();//返回[1,2,3,4,5,6]
方法4:数组递归去重
Array.prototype.removal = function(){
var arr = this,
len = arr.length;
arr.sort(function(a,b){
return a - b;
})
function loop(index){
if(index >= 1){
if(arr[index] === arr[index-1]){
arr.splice(index,1);
}
loop(index - 1);
}
}
loop(len-1);
return arr;
}
var arr1 = [1,2,3,4,2,3,1,4,5,6,6];
arr1.removal();//返回[1,2,3,4,5,6]
方法5:利用indexOf以及forEach
Array.prototype.removal = function (){
var arr = this,
result = [],
len = arr.length;
arr.forEach(function(v, i ,arr){
var bool = arr.indexOf(v,i+1);
if(bool === -1){
result.push(v);
}
})
return result;
};
var arr1 = [1,2,3,4,2,3,1,4,5,6,6];
arr1.removal();//返回[1,2,3,4,5,6]
方法6.利用ES6的set
function removal(arr){
return Array.from(new Set(arr));
}
removal([1,2,3,4,2,3,1,4,5,6,6]);//返回[1,2,3,4,5,6]
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