# sort是会影响列表本身
lis = [4,5,68,46,4,]
lis.sort()
print(lis)
[4, 4, 5, 46, 68]
sorted
dic = {0: 9, 1: 0, 2: 3, 3: 3, 4: 1, 5: 7, 6: 4}
# 将字典items键值对组成元组传入,取每个元组[1]元素进行排序,reverse表示升降序
b = dict(sorted(dic.items(),key=lambda x:x[1],reverse=True))
print(b)
{0: 9, 5: 7, 6: 4, 2: 3, 3: 3, 4: 1, 1: 0}
portfolio = [
{'name': 'IBM', 'shares': 100, 'price': 91.1},
{'name': 'AAPL', 'shares': 50, 'price': 543.22},
{'name': 'FB', 'shares': 200, 'price': 21.09},
{'name': 'HPQ', 'shares': 35, 'price': 31.75},
{'name': 'YHOO', 'shares': 45, 'price': 16.35},
{'name': 'ACME', 'shares': 75, 'price': 115.65}
]
a = sorted([i for i in portfolio],key=lambda x:x['price'],reverse=True)
print(a)
- 模块
heapq
方法
- 传入三个参数,
nsmallest(n, iterable, key=None)
-
n
-> 排序的数量
-
iterable
-> 要排序的可迭代对象
-
key
-> 排序的关键字
import heapq
portfolio = [
{'name': 'IBM', 'shares': 100, 'price': 91.1},
{'name': 'AAPL', 'shares': 50, 'price': 543.22},
{'name': 'FB', 'shares': 200, 'price': 21.09},
{'name': 'HPQ', 'shares': 35, 'price': 31.75},
{'name': 'YHOO', 'shares': 45, 'price': 16.35},
{'name': 'ACME', 'shares': 75, 'price': 115.65}
]
# 升序
cheap = heapq.nsmallest(len(portfolio),portfolio, key=lambda s: s['price'])
print(cheap)
[{'name': 'YHOO', 'price': 16.35, 'shares': 45},
{'name': 'FB', 'price': 21.09, 'shares': 200},
{'name': 'HPQ', 'price': 31.75, 'shares': 35},
{'name': 'IBM', 'price': 91.1, 'shares': 100},
{'name': 'ACME', 'price': 115.65, 'shares': 75},
{'name': 'AAPL', 'price': 543.22, 'shares': 50}]
# 降序
expensive = heapq.nlargest(3, portfolio, key=lambda s: s['price'])
print(expensive)
[{'name': 'AAPL', 'price': 543.22, 'shares': 50},
{'name': 'ACME', 'price': 115.65, 'shares': 75},
{'name': 'IBM', 'price': 91.1, 'shares': 100}]
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