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leetcode题目23. 合并K个排序链表(java)

leetcode题目23. 合并K个排序链表(java)

作者: castlet | 来源:发表于2020-06-06 22:23 被阅读0次

    题目描述

    合并 k 个排序链表,返回合并后的排序链表。请分析和描述算法的复杂度。

    示例

    输入:
    [
      1->4->5,
      1->3->4,
      2->6
    ]
    输出: 1->1->2->3->4->4->5->6
    

    解题思路

    分而治之,链表两两合并

    代码

    public ListNode mergeKLists(ListNode[] lists){
        if (lists.length == 0) {
            return null;
        }
        return merge(lists, 0, lists.length - 1);
    }
    
    public ListNode merge(ListNode[] lists, int left, int right){
        if (left == right) {
            return lists[left];
        }
        int middle = left + (right - left) / 2;
        ListNode l1 = merge(lists, left, middle);
        ListNode l2 = merge(lists, middle + 1, right);
        return mergeTwoLists(l1, l2);
    }
    public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
        if (l1 == null) {
            return l2;
        }
        if (l2 == null) {
            return l1;
        }
        ListNode newHead = null;
        if (l1.val < l2.val) {
            newHead = l1;
            l1 = l1.next;
        } else {
            newHead = l2;
            l2 = l2.next;
        }
        ListNode cur = newHead;
        while (l1 != null && l2 != null) {
            if (l1.val < l2.val) {
                cur.next = l1;
                l1 = l1.next;
            } else {
                cur.next = l2;
                l2 = l2.next;
            }
            cur = cur.next;
        }
    
        if (l1 != null) {
            cur.next = l1;
        } else if (l2 != null) {
            cur.next = l2;
        }
        return newHead;
    }
    

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