题目
Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n.
答案
class Solution {
public int numSquares(int n) {
// f[i]: numSquares(i)
// think: how does f[i] depend on f[j], j < i?
// f[i] = f[i - some perfect square]
int[] f = new int[n + 1];
f[0] = 0;
for(int i = 1; i <= n; i++) {
f[i] = Integer.MAX_VALUE;
for(int j = 1; j*j <= n; j++) {
if(i - j*j < 0) break;
f[i] = Math.min(f[i], f[i - j*j] + 1);
}
//System.out.println(f[i]);
}
return f[n];
}
}
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