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《GO语言圣经》读书笔记 第二章 习题解答

《GO语言圣经》读书笔记 第二章 习题解答

作者: bocsoft | 来源:发表于2020-04-08 22:22 被阅读0次

    练习 2.1: 向tempconv包添加类型、常量和函数用来处理Kelvin绝对温度的转换,Kelvin 绝对零度是−273.15°C,Kelvin绝对温度1K和摄氏度1°C的单位间隔是一样的

    
    package tempconv
    
    import "fmt"
    
    type Celsius float64
    type Fahrenheit float64
    type Kelvin float64
    
    const (
        AbsoluteZeroC Celsius = -273.15
        FreezingC Celsius = 0
        BoilingC Celsius = 100
    )
    
    func (c Celsius) String() string    { return fmt.Sprintf("%g°C", c) }
    func (f Fahrenheit) String() string { return fmt.Sprintf("%g°F", f) }
    func (k Kelvin) String() string     { return fmt.Sprintf("%gK", k) }
    
    func CToF(c Celsius) Fahrenheit { return Fahrenheit(c*9/5 + 32) }
    func FToC(f Fahrenheit) Celsius { return Celsius((f - 32) * 5 / 9) }
    
    func CToK(c Celsius) Kelvin {return Kelvin(c + AbsoluteZeroC)}
    func KToC(k Kelvin) Celsius { return Celsius(k) - AbsoluteZeroC}
    
    
    package main
    
    import (
        "fmt"
        "./tempconv"
    )
    
    
    func main() {
        fmt.Println("AbsoluteZeroK:",tempconv.CToK(tempconv.AbsoluteZeroC))
        fmt.Println("FreezingK:",tempconv.CToK(tempconv.FreezingC))
        fmt.Println("BoilinigK:",tempconv.CToK(tempconv.BoilingC))
    }
    
    

    练习 2.2: 写一个通用的单位转换程序,用类似cf程序的方式从命令行读取参数,如果缺省的话则是从标准输入读取参数,然后做类似Celsius和Fahrenheit的单位转换,长度单位可以对应英尺和米,重量单位可以对应磅和公斤等。

    package main
    
    import (
        "fmt"
        "os"
        "bufio"
        "strings"
        "strconv"
        "../ex01/tempconv"
    )
    
    type Meter float64
    type Feet float64
    type Pound float64
    type Kilogram float64
    
    func (m Meter) String() string {return fmt.Sprintf("%gm",m)}
    func (f Feet) String() string {return fmt.Sprintf("%gft",f)}
    func (p Pound) String() string {return fmt.Sprintf("%glb",p)}
    func (k Kilogram) String() string {return fmt.Sprintf("%gkg",k)}
    
    func MToF(m Meter) Feet {return Feet(m * 1200 / 3937)}
    func FToM(f Feet) Meter {return Meter(f * 3937 / 1200)}
    func PToK(p Pound) Kilogram {return Kilogram( p * 0.45359237)}
    func KToP(k Kilogram) Pound { return Pound(k / 0.45359237)}
    
    
    func main() {
        var args []string
        if len(os.Args) > 1 {
            args = os.Args[1:]
        }else{
            r := bufio.NewReader(os.Stdin)
            s, _ := r.ReadString('\n')
            args = []string{strings.TrimSpace(s)}
        }
    
        for _,arg := range args {
            v, err := strconv.ParseFloat(arg, 64)
            if err != nil {
                fmt.Fprintf(os.Stderr,"unitconv: %v\n",err)
                os.Exit(1)
            }
            {
                f := tempconv.Fahrenheit(v)
                c := tempconv.Celsius(v)
                fmt.Printf("%s = %s,%s = %s\n",f,tempconv.FToC(f),c,tempconv.CToF(c))
            }
            {
                m := Meter(v)
                f := Feet(v)
                fmt.Printf("%s = %s,%s = %s\n",m,MToF(m),f,FToM(f))
            }
            {
                p := Pound(v)
                k := Kilogram(v)
                fmt.Printf("%s = %s, %s = %s\n",p,PToK(p),k,KToP(k))
            }
        }
    }
    
    
    

    练习 2.3: 重写PopCount函数,用一个循环代替单一的表达式。比较两个版本的性能。(11.4节将展示如何系统地比较两个不同实现的性能。

    package popcount
    
    // pc[i] is the population count of i.
    var pc [256]byte
    
    func init() {
        for i := range pc {
            pc[i] = pc[i/2] + byte(i&1)
        }
    }
    
    // PopCount returns the population count (number of set bits) of x.
    func PopCount(x uint64) int {
        return int(pc[byte(x>>(0*8))] +
            pc[byte(x>>(1*8))] +
            pc[byte(x>>(2*8))] +
            pc[byte(x>>(3*8))] +
            pc[byte(x>>(4*8))] +
            pc[byte(x>>(5*8))] +
            pc[byte(x>>(6*8))] +
            pc[byte(x>>(7*8))])
    }
    
    func PopCountByLoop(x uint64) int {
        n := 0
        for i := byte(0); i < 8; i++ {
            n += int(pc[byte(x >>(i*8))])
        }
        return n
    }
    
    
    package popcount
    
    import (
        "testing"
        "reflect"
    )
    
    func assert(t *testing.T,expected,actual interface{}){
        if !reflect.DeepEqual(expected,actual){
            t.Errorf("(expected,actual) = (%v,%v)\n",expected,actual)
        }
    }
    
    func TestPopCount(t *testing.T) {
        assert(t,32,PopCount(0x1234567890ABCDEF))
    }
    
    
    func TestPopCountByLoop(t *testing.T) {
        assert(t, 32, PopCountByLoop(0x1234567890ABCDEF))
    }
    
    func BenchmarkPopCount(b *testing.B) {
        for i := 0; i < b.N; i++ {
            PopCount(0x1234567890ABCDEF)
        }
    }
    
    func BenchmarkPopCountByLoop(b *testing.B) {
        for i := 0; i < b.N; i++ {
            PopCountByLoop(0x1234567890ABCDEF)
        }
    }
    

    练习 2.4: 用移位算法重写PopCount函数,每次测试最右边的1bit,然后统计总数。比较和查表算法的性能差异。

    package popcount
    
    // pc[i] is the population count of i.
    var pc [256]byte
    
    func init() {
        for i := range pc {
            pc[i] = pc[i/2] + byte(i&1)
        }
    }
    
    // PopCount returns the population count (number of set bits) of x.
    func PopCount(x uint64) int {
        return int(pc[byte(x>>(0*8))] +
            pc[byte(x>>(1*8))] +
            pc[byte(x>>(2*8))] +
            pc[byte(x>>(3*8))] +
            pc[byte(x>>(4*8))] +
            pc[byte(x>>(5*8))] +
            pc[byte(x>>(6*8))] +
            pc[byte(x>>(7*8))])
    }
    
    func PopCountByBitShift(x uint64) int {
        n := 0
        for i := uint(0); i < 64; i++ {
            if (x>>i)&1 != 0 {
                n++
            }
        }
        return n
    }
    
    package popcount
    
    import (
        "reflect"
        "testing"
    )
    
    func assert(t *testing.T, expected, actual interface{}) {
        if !reflect.DeepEqual(expected, actual) {
            t.Errorf("(expected, actual) = (%v, %v)\n", expected, actual)
        }
    }
    
    func TestPopCount(t *testing.T) {
        assert(t, 32, PopCount(0x1234567890ABCDEF))
    }
    
    func TestPopCountByBitShift(t *testing.T) {
        assert(t, 32, PopCountByBitShift(0x1234567890ABCDEF))
    }
    
    func BenchmarkPopCount(b *testing.B) {
        for i := 0; i < b.N; i++ {
            PopCount(0x1234567890ABCDEF)
        }
    }
    
    func BenchmarkPopCountByBitShift(b *testing.B) {
        for i := 0; i < b.N; i++ {
            PopCountByBitShift(0x1234567890ABCDEF)
        }
    }
    
    
    

    练习 2.5: 表达式x&(x-1)用于将x的最低的一个非零的bit位清零。使用这个算法重写PopCount函数,然后比较性能。

    package popcount
    
    // pc[i] is the population count of i.
    var pc [256]byte
    
    func init() {
        for i := range pc {
            pc[i] = pc[i/2] + byte(i&1)
        }
    }
    
    // PopCount returns the population count (number of set bits) of x.
    func PopCount(x uint64) int {
        return int(pc[byte(x>>(0*8))] +
            pc[byte(x>>(1*8))] +
            pc[byte(x>>(2*8))] +
            pc[byte(x>>(3*8))] +
            pc[byte(x>>(4*8))] +
            pc[byte(x>>(5*8))] +
            pc[byte(x>>(6*8))] +
            pc[byte(x>>(7*8))])
    }
    
    func PopCountByBitClear(x uint64) int {
        n := 0
        for x != 0 {
            x = x & (x - 1)
            n++
        }
        return n
    }
    
    package popcount
    
    import (
        "reflect"
        "testing"
    )
    
    func assert(t *testing.T, expected, actual interface{}) {
        if !reflect.DeepEqual(expected, actual) {
            t.Errorf("(expected, actual) = (%v, %v)\n", expected, actual)
        }
    }
    
    func TestPopCount(t *testing.T) {
        assert(t, 32, PopCount(0x1234567890ABCDEF))
    }
    
    func TestPopCountByBitClear(t *testing.T) {
        assert(t, 32, PopCountByBitClear(0x1234567890ABCDEF))
    }
    
    func BenchmarkPopCount(b *testing.B) {
        for i := 0; i < b.N; i++ {
            PopCount(0x1234567890ABCDEF)
        }
    }
    
    func BenchmarkPopCountByBitClear(b *testing.B) {
        for i := 0; i < b.N; i++ {
            PopCountByBitClear(0x1234567890ABCDEF)
        }
    }
    
    

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