1.19 实现一个容器, 有两个要求: 1. add(), si

/**
 * This is description.
 * 面试题: 实现一个容器, 有两个要求:
 * 1. add, size.
 * 2. 写2个线程, 线程1添加10个元素到容器中, 线程2实现监控元素个数, 当个数到达5个时, 线程2给出提示并结束(线程2结束).
 * Container3利用wait和notify优化Container2的while(true){...}死循环.
 *
 * @author Chris Lee
 * @date 2019/3/16 9:59
 */
public class Container3 {
    volatile List<Object> list = new ArrayList<>(10);

    public void add(Object object) {
        list.add(object);
    }

    public int size() {
        return list.size();
    }

    public static void main(String[] args) {
        Container2 container1 = new Container2();
        Object lock = new Object();

        new Thread(() -> {
            synchronized (lock) {
                System.out.println("当前线程名: " + Thread.currentThread().getName() + "启动.");
                if (container1.size() != 5) {
                    try {
                        lock.wait();
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                }
                System.out.println("当前线程名: " + Thread.currentThread().getName() + "结束.");

            }

        }, "t2").start();

        try {
            TimeUnit.SECONDS.sleep(1);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }

        new Thread(() -> {
            synchronized (lock) {
                for (int i = 0; i < 10; i++) {
                    container1.add(new Object());
                    System.out.println("当前线程名: " + Thread.currentThread().getName() + ", i = " + i);
                    if (container1.size() == 5) {
                        lock.notify();
                    }
                    try {
                        TimeUnit.SECONDS.sleep(1);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                }
            }
        }, "t1").start();

    }
    /*
        当前线程名: t2启动.
        当前线程名: t1, i = 0
        当前线程名: t1, i = 1
        当前线程名: t1, i = 2
        当前线程名: t1, i = 3
        当前线程名: t1, i = 4
        当前线程名: t1, i = 5
        当前线程名: t1, i = 6
        当前线程名: t1, i = 7
        当前线程名: t1, i = 8
        当前线程名: t1, i = 9
        当前线程名: t2结束.
     */

}

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资料:

1. 学习视频: https://www.bilibili.com/video/av11076511/?p=1
2. 参考代码: https://github.com/EduMoral/edu/tree/master/concurrent/src/yxxy
3. 我的代码: https://github.com/ChrisLeejing/learn_concurrency.git