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lint0005. Kth Largest Element

lint0005. Kth Largest Element

作者: 日光降临 | 来源:发表于2019-03-03 22:25 被阅读0次

    Find K-th largest element in an array.
    Example 1:
    Input:
    n = 1, nums = [1,3,4,2]
    Output:
    4

    Example 2:
    Input:
    n = 3, nums = [9,3,2,4,8]
    Output:
    4
    Challenge
    O(n) time, O(1) extra memory.

    class Solution {
        /*
         * @param k : description of k
         * @param nums : array of nums
         * @return: description of return
         */
        public int kthLargestElement(int k, int[] nums) {
            if (nums == null || nums.length == 0 || k < 1 || k > nums.length){
                return -1;
            }
            return partition(nums, 0, nums.length - 1, nums.length - k);
        }
        
        private int partition(int[] nums, int start, int end, int k) {
            if (start >= end) {
                return nums[k];
            }
            
            int left = start, right = end;
            int pivot = nums[(start + end) / 2];
            
            while (left <= right) {
                while (left <= right && nums[left] < pivot) {
                    left++;
                }
                while (left <= right && nums[right] > pivot) {
                    right--;
                }
                if (left <= right) {
                    swap(nums, left, right);
                    left++;
                    right--;
                }
            }
            
            if (k <= right) {
                return partition(nums, start, right, k);
            }
            if (k >= left) {
                return partition(nums, left, end, k);
            }
            return nums[k];
        }    
        
        private void swap(int[] nums, int i, int j) {
            int tmp = nums[i];
            nums[i] = nums[j];
            nums[j] = tmp;
        }
    };
    
    class Solution {
        /*
         * @param k : description of k
         * @param nums : array of nums
         * @return: description of return
         */
        public int kthLargestElement(int k, int[] nums) {
    
            // write your code here
            int low = 0, high = nums.length -1;
            while(low <= high){
                int index = low-1;
                for(int i = low; i < high; i++){
                    if(nums[i] > nums[high]){
                        swap(nums, i, ++index);
                    }
                }
                swap(nums, ++index, high);
                if(index == k - 1){
                    return nums[index];
                }
                if(index < k -1){
                    low = index + 1;
                }else{
                    high = index - 1;
                }
            }
            return -1;
        }
        
        private void swap(int[] nums, int a, int b){
            int temp = nums[a];
            nums[a] = nums[b];
            nums[b] = temp;
        }
    };
    

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