匿名函数 lambda
>>> f = lambda x, y: x+y
>>>f(2, 3)
5
等于
def f(x,y):
return x+y
函数传递
def add(y):
return y*y
def count(f, x):
print( f(x))
r = count(add, 2)
或者
def add(y):
return y*y
def count(f, x):
return f(x)
r = count(add, 2)
print(r)
将函数作为参数进行传递
网友评论