七、python简单示例

def checkio(data):
import re
# re模块的search函数，匹配data中的partten，如果找不到匹配，则返回None
lower = re.search('[a-z]', data)
upper = re.search('[A-Z]', data)
digit = re.search('[0-9]', data)
return all((lower, upper, digit, len(data)>= 10))

 from collections import Counter
 import string
 import re
 
 def checkio(text):
     # 得到文本中的字符序列，过滤掉特殊字符
     re_letter = re.compile('[a-zA-Z]')
     text_letter = re_letter.findall(text.lower())
     # 对字符出现的次数进行统计
     c = Counter(text_letter)
     statistics_text = c.most_common()
     # 获取出现次数最多的字符出现的次数
     times = statistics_text[0][1]
     # 获取出现次数最多的字符的列表
     most_list = [statistics_text[i][0] for i in range(len(statistics_text))
                  if statistics_text[i][1] == times]
     # 忽略大小写进行排序
     most_list_sorted = sorted(most_list, key=str.lower)
     return most_list_sorted[0]

from collections import Counter
def checkio(data):
    counter_data = Counter(data)
    uniq_items = [i for i in data if counter_data[i] == 1]
    for i in range(len(uniq_items)):
        data.remove(uniq_items[i])

return data

 import re
 def count_words(text, words):
     text_lower = text.lower()
     count = 0
     for word in words:
         if re.search(word, text_lower):
             count += 1
     return count

return sum([ w in text.lower() for w in words])