WEEK#1 Minimum Number of Arrows

1. Sort the bullons by their ending points
2. Each time we shoot an arrow aiming at the smallest ending point and remove all the bullons that are bursted by this arrow
3. Continue to do step 2 until all bullons are bursted

bool mycompare(pair<int,int> p1, pair<int,int> p2) {
    return p1.second < p2.second || (p1.second == p2.second && p1.first < p2.first);
}

class Solution {
public:
    int findMinArrowShots(vector<pair<int, int>>& points) {
        sort(points.begin(), points.end(), mycompare);
        
        int Count = 0;
        while (!points.empty()) {
            int CurrentArrow = points.front().second;
            //cout << "CurrentArrow = " << CurrentArrow << endl;
            Count++;
            for (int i = 0; i < points.size(); i++) {
                if (CurrentArrow >= points[i].first && CurrentArrow <= points[i].second) {
                    //cout << "i = " << i << endl;
                    //cout << "points[i].first = " << points[i].first << " points[i].second = " << points[i].second << endl;
                    points.erase(points.begin() + i);
                    i = -1;
                }
            }
        }
        return Count;
    }
};