1002 A+B for Polynomials (25 分)
#include<bits/stdc++.h>
using namespace std;
double n[1001];
int main(){
int k,a,t=2,cnt=0;
double b;
while(t--){
cin>>k;
while(k--){
cin>>a>>b;
n[a]+=b;
}
}
for(int i=1000;i>=0;i--){
if(n[i]!=0)cnt++;
}
cout<<cnt;
for(int i=1000;i>=0;i--){
if(n[i]!=0)printf(" %d %.1f",i,n[i]);
}
return 0;
}
1002 A+B for Polynomials (25 分)
1002 A+B for Polynomials (25)（25 分） This time, you are su...
1002 A+B for Polynomials （25 分） This time, you are suppos...
1002 A+B for Polynomials (25)This time, you are supposed ...
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原题链接 1002 A+B for Polynomials （25 分） 【题目大意】给定两个多项式A和B，输出 ...
1002. A+B for Polynomials (25) 时间限制400 ms内存限制65536 kB代码长度...
A+B for Polynomials (25 分) 题目描述：This time, you are suppos...
This time, you are supposed to find A+B where A and B are...
本文标题：1002 A+B for Polynomials (25 分)
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