Pat1002 A+B for Polynomials(25)

Pat1002 A+B for Polynomials(25)

This time, you are supposed to find A+B where A and B are two polynomials.

Input

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10，0 <= NK < ... < N2 < N1 <=1000.

Output

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input
2 1 2.4 0 3.2
2 2 1.5 1 0.5
Sample Output
3 2 1.5 1 2.9 0 3.2

说一下遇到的问题：

• 格式错误，要求跟输入一样，浮点书表留一位小数，最后不能由空格
• 没有考虑到如果两个多项式相加，会出现系数为0的情况，此时不再记录（多虑的是demo分明由0输出了么，但是它是指数不是系数）
• 数据的类型，一定尽量开始就合适

我的代码

 #include <map>
 #include <iostream>
 #include<iterator>
 #include <iomanip>
using namespace std;
map<int,double> da;
int main()
{
    int size;
    int tmp1;
    double tmp2;
    cin>>size;
        for(int i=0;i<size;++i)
        {
            cin>>tmp1;
            cin>>tmp2;
            da[tmp1]+=tmp2;
        }
        cin>>size;
        for(int i=0;i<size;++i)
        {
            cin>>tmp1;
            cin>>tmp2;
            da[tmp1]+=tmp2;
        if(da[tmp1]==0)
            da.erase(tmp1);
        }
    cout<<da.size();
    for(map<int,double>::reverse_iterator s=da.rbegin();s!=da.rend();++s)
    {
        cout<<fixed<<setprecision(1);
        cout<<" "<<s->first<<" "<<s->second;
    }
    cout<<endl;
    return 0;
}