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golang 获取本周时间

golang 获取本周时间

作者: Feng_Sir | 来源:发表于2018-05-16 10:11 被阅读0次
## [mysql获取当天,昨天,本周,本月,上周,上月的起始时间](http://www.cppblog.com/tx7do/archive/2017/07/19/215119.html)

-- 今天  SELECT DATE_FORMAT(NOW(),'%Y-%m-%d 00:00:00') AS '今天开始';
SELECT DATE_FORMAT(NOW(),'%Y-%m-%d 23:59:59') AS '今天结束';

-- 昨天  SELECT DATE_FORMAT( DATE_SUB(CURDATE(), INTERVAL 1 DAY), '%Y-%m-%d 00:00:00') AS '昨天开始';
SELECT DATE_FORMAT( DATE_SUB(CURDATE(), INTERVAL 1 DAY), '%Y-%m-%d 23:59:59') AS '昨天结束';

-- 上周  SELECT DATE_FORMAT( DATE_SUB( DATE_SUB(CURDATE(), INTERVAL WEEKDAY(CURDATE()) DAY), INTERVAL 1 WEEK), '%Y-%m-%d 00:00:00') AS '上周一';
SELECT DATE_FORMAT( SUBDATE(CURDATE(), WEEKDAY(CURDATE()) + 1), '%Y-%m-%d 23:59:59') AS '上周末';

-- 本周  SELECT DATE_FORMAT( SUBDATE(CURDATE(),DATE_FORMAT(CURDATE(),'%w')-1), '%Y-%m-%d 00:00:00') AS '本周一';
SELECT DATE_FORMAT( SUBDATE(CURDATE(),DATE_FORMAT(CURDATE(),'%w')-7), '%Y-%m-%d 23:59:59') AS '本周末';
-- 上面的本周算法会有问题,因为mysql是按照周日为一周第一天,如果当前是周日的话,会把时间定为到下一周.  SELECT DATE_FORMAT( DATE_SUB(CURDATE(), INTERVAL WEEKDAY(CURDATE()) DAY), '%Y-%m-%d 00:00:00') AS '本周一';
SELECT DATE_FORMAT( DATE_ADD(SUBDATE(CURDATE(), WEEKDAY(CURDATE())), INTERVAL 6 DAY), '%Y-%m-%d 23:59:59') AS '本周末';

-- 上月  SELECT DATE_FORMAT( DATE_SUB(CURDATE(), INTERVAL 1 MONTH), '%Y-%m-01 00:00:00') AS '上月初';
SELECT DATE_FORMAT( LAST_DAY(DATE_SUB(CURDATE(), INTERVAL 1 MONTH)), '%Y-%m-%d 23:59:59') AS '上月末';

-- 本月  SELECT DATE_FORMAT( CURDATE(), '%Y-%m-01 00:00:00') AS '本月初';
SELECT DATE_FORMAT( LAST_DAY(CURDATE()), '%Y-%m-%d 23:59:59') AS '本月末';

去mysql数据库获取好了 哈哈哈哈哈哈

weekMap,error := goblet.DB.QueryString("SELECT DATE_FORMAT( DATE_SUB(CURDATE(), INTERVAL WEEKDAY(CURDATE()) DAY), '%Y%m%d000000') AS 'startWeek'," +
            "DATE_FORMAT( DATE_ADD(SUBDATE(CURDATE(), WEEKDAY(CURDATE())), INTERVAL 6 DAY), '%Y%m%d235959') AS 'endWeek'")
        fmt.Println(weekMap,error)
[xorm] [info]  2018/05/16 10:07:04.421778 [SQL] SELECT DATE_FORMAT( DATE_SUB(CURDATE(), INTERVAL WEEKDAY(CURDATE()) DAY), '%Y%m%d000000') AS 'startWeek',DATE_FORMAT( DATE_ADD(SUBDATE(CURDATE(), WEEKDAY(CURDATE())), INTERVAL 6 DAY), '%Y%m%d235959') AS 'endWeek'
[map[startWeek:20180514000000 endWeek:20180520235959]] <nil>

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