etcd分布式锁

作者: meng256011 | 来源:发表于2019-07-03 00:21 被阅读0次

    1.实现带租约(lease)的分布式锁,如果分布式租约到期,则自动释放锁。

    package main
    
    import (
        "context"
        "fmt"
        "log"
        "os"
        "time"
    
        "github.com/coreos/etcd/clientv3"
        "github.com/etcd-io/etcd/clientv3/concurrency"
    )
    
    var c chan int
    
    func init() {
        c = make(chan int)
    }
    
    func main() {
        // 创建client链接服务器,指定Config中的DialTimeout表示链接DialTimeout时间后没有链接上则返回error
        client, err := clientv3.New(clientv3.Config{
            Endpoints: []string{"http://localhost:2379"},
        })
        if err != nil {
            panic(err)
        }
    
        // 监听/foobar事件
        watcher := clientv3.NewWatcher(client)
        channel := watcher.Watch(context.Background(), "/foobar", clientv3.WithPrefix())
        go func() {
            for {
                select {
                case change := <-channel:
                    for _, ev := range change.Events {
                        log.Printf("etcd change on key; %s, type = %v", string(ev.Kv.Key), ev.Type)
                    }
                }
            }
        }()
    
        go lockFoobar(client, 1)
        time.Sleep(time.Second)
        go lockFoobar(client, 2)
        <-c
        <-c
    }
    
    func lockFoobar(client *clientv3.Client, id int) {
        // 创建一个10s的租约(lease)
        res, err := client.Grant(context.Background(), 10)
        if err != nil {
            panic(err)
        }
        // 利用上面创建的租约ID创建一个session
        session, err := concurrency.NewSession(client, concurrency.WithLease(res.ID))
        if err != nil {
            panic(err)
        }
        // 创建以/foobar为前缀的锁,上面监听的和这里的要相同
        mux := concurrency.NewMutex(session, "/foobar")
    
        log.Printf("trying to lock by #%d\n", id)
        // 获取锁使用context.Background()会一直获取锁直到获取成功
        // 如果这里使用context.WithTimeout(context.Background(), 10*time.Second)
        // 表示获取锁10s如果没有获取成功则返回error。
        if err := mux.Lock(context.Background()); err != nil {
            log.Printf("failed to lock #%d: %v\n", id, err)
            c <- id
            return
        }
        // 注意在获取锁后要调用该函数在session的租约到期后才会释放锁。
        session.Orphan()
    
        log.Printf("post-lock #%d (lease ID = %x) get succeed!\n", id, res.ID)
        time.Sleep(20 * time.Second)
        // 获取租约的详细信息
        //ttl, _ := client.TimeToLive(context.TODO(), res.ID)
        //log.Printf("post-post-lock-#%d-sleep. lease ttl = %v", id, ttl.TTL)
        // 这里为了测试在不释放锁的情况下,后面的的所是否能上锁成功
        // mux.Unlock(ctx)
        // log.Printf("post-unlock #%d bullshit\n", id)
    
        time.Sleep(200 * time.Millisecond)
        c <- id
    }
    

    session.Orphan()解释见该链接

    2.实现无租约阻塞分布式锁

    
    
    func main() {
        cli, err := clientv3.New(clientv3.Config{Endpoints: []string{"localhost:2379"}, DialTimeout: 5 * time.Second})
        if err != nil {
            log.Println("connect failed, err:", err)
            return
        }
        // 如果task1进程挂掉,则链接会断开那么
        //defer cli.Close()
    
        // ss1, err := concurrency.NewSession(cli,  concurrency.WithTTL(1))给创建的session一个1s的alive时期,即如果task1所在的进程挂掉,则ss1会被server在1s后关掉,这样task2就能立即获取成功锁
        // concurrency.WithContext(context.Background())使用该参数生成session会默认在task1所在的进程挂掉,则ss1会被server在60s后关掉,这样task2就能立即获取成功锁.
        // 所以若想让task2立即获取锁则应该使用
        // ss1, err := concurrency.NewSession(cli,  concurrency.WithTTL(1))
        ss1, err := concurrency.NewSession(cli, concurrency.WithContext(context.Background()))
        if err != nil {
            log.Fatal(err)
        }
        //defer ss1.Close()
    
        mu1 := concurrency.NewMutex(ss1, "/my-lock/")
        fmt.Println("try get lock1 ... ")
        // try get lock util context expire, if Lock() uses context.Background(), it will acquire lock forever
        err = mu1.Lock(context.Background())
        if err != nil {
            fmt.Println("get lock1 failed!")
            os.Exit(0)
        }
    
        fmt.Println("get lock1 succeed!")
    
        doCancel := func() {
            fmt.Println("try free lock1 ...!")
            err = mu1.Unlock(context.Background())
            if err != nil {
                //ss1.Close()
                //cli.Close()
                fmt.Println("free lock1 failed!")
                os.Exit(0)
            }
            //ss1.Close()
            //cli.Close()
            fmt.Println("free lock1 succeed!")
        }
    
        go func() {
            time.Sleep(15 * time.Second)
            doCancel()
        }()
    
        time.Sleep(2000*time.Second)
    }
    
    package main
    
    
    import (
        "context"
        "fmt"
        "log"
        "os"
        "time"
    
        "github.com/coreos/etcd/clientv3"
        "github.com/etcd-io/etcd/clientv3/concurrency"
    )
    
    func main() {
        cli, err := clientv3.New(clientv3.Config{Endpoints: []string{"localhost:2379"}, DialTimeout: 5 * time.Second})
        if err != nil {
            log.Println("connect failed, err:", err)
            return
        }
        //defer cli.Close()
    
        ss2, err := concurrency.NewSession(cli,  concurrency.WithContext(context.Background()))
        if err != nil {
            log.Fatal(err)
        }
        //defer ss2.Close()
    
        mu2 := concurrency.NewMutex(ss2, "/my-lock/")
        fmt.Println("try get lock2 ... ")
        err = mu2.Lock(context.Background())
        if err != nil {
            fmt.Println("get lock2 failed!")
            os.Exit(0)
        }
        fmt.Println("get lock2 succeed!")
    
        fmt.Println("try free lock2 ...!")
        err = mu2.Unlock(context.Background())
        if err != nil {
            fmt.Println("free lock2 failed!")
            os.Exit(0)
        }
        fmt.Println("free lock2 succeed!")
        time.Sleep(2000*time.Second)
    }
    

    先运行第一个main.go,lock1获取成功。再运行第二个main.go,会一直阻塞获取lock2,这时候kill掉第一个main.go的进程,会看到第二个lock2会立即获取成功。

    相关文章

      网友评论

        本文标题:etcd分布式锁

        本文链接:https://www.haomeiwen.com/subject/aqdxhctx.html