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36. 有效的数独

36. 有效的数独

作者: 凌霄文强 | 来源:发表于2019-03-13 19:51 被阅读0次

    题目描述

    判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。

    数字 1-9 在每一行只能出现一次。
    数字 1-9 在每一列只能出现一次。
    数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。

    数独部分空格内已填入了数字,空白格用 '.' 表示。

    示例 1:

    输入:
    [
    ["5","3",".",".","7",".",".",".","."],
    ["6",".",".","1","9","5",".",".","."],
    [".","9","8",".",".",".",".","6","."],
    ["8",".",".",".","6",".",".",".","3"],
    ["4",".",".","8",".","3",".",".","1"],
    ["7",".",".",".","2",".",".",".","6"],
    [".","6",".",".",".",".","2","8","."],
    [".",".",".","4","1","9",".",".","5"],
    [".",".",".",".","8",".",".","7","9"]
    ]
    输出: true
    示例 2:

    输入:
    [
    ["8","3",".",".","7",".",".",".","."],
    ["6",".",".","1","9","5",".",".","."],
    [".","9","8",".",".",".",".","6","."],
    ["8",".",".",".","6",".",".",".","3"],
    ["4",".",".","8",".","3",".",".","1"],
    ["7",".",".",".","2",".",".",".","6"],
    [".","6",".",".",".",".","2","8","."],
    [".",".",".","4","1","9",".",".","5"],
    [".",".",".",".","8",".",".","7","9"]
    ]
    输出: false
    解释: 除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。
    但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。
    说明:

    一个有效的数独(部分已被填充)不一定是可解的。
    只需要根据以上规则,验证已经填入的数字是否有效即可。
    给定数独序列只包含数字 1-9 和字符 '.' 。
    给定数独永远是 9x9 形式的。

    知识点

    数组


    Qiang的思路

    class Solution:
        def getResult(self, line: List[str]) -> bool:
            flag=[0 for i in range(10)]
            for c in line:
                if c=='.':
                    continue
                if flag[int(c)]==1:
                    return False
                flag[int(c)]=1
            return True
        
        def isValidSudoku(self, board: List[List[str]]) -> bool:
            for i in range(9):
                line=[a for a in board[i]]
                if self.getResult(line)==False:
                    return False
            for i in range(9):
                line=[b for a in board for b in a[i]]
                if self.getResult(line)==False:
                    return False
            for i in range(3):
                for j in range(3):
                    line=[b for a in board[i*3:(i+1)*3] for b in a[j*3:(j+1)*3]]
                    if self.getResult(line)==False:
                        return False
            return True
    

    作者原创,如需转载及其他问题请邮箱联系:lwqiang_chn@163.com
    个人网站:https://www.myqiang.top

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