计数排序
- 时间复杂度(平均、最坏、最好) O(n+k)
- 空间复杂度为O(n+k)
- 稳定性:稳定
- n为数组元素个数,k为数据最大值
算法解析:
- 计数排序不是比较数值排序,是记录数据出现次数的一种排序算法
- 找出待排数组中最大值
- 额外一个数组记录待排数组值出现的次数
- 循环打印存储数值次数的数组下标值
动画演示:
countingSort
C实现
int * countingSort1(int arr[],int count,int max) {
int index = 0;
int *tmpArr = (int *)malloc(max*sizeof(int));
int *result = (int *)malloc(max*sizeof(int));
for(int k = 0;k<max;k++) {
tmpArr[k] = 0;
}
for (int i = 0; i<count; i++) {
tmpArr[arr[i]]++;
}
for (int j = 0; j<max; j++) {
while (tmpArr[j]) {
result[index++] = j;
tmpArr[j]--;
}
}
free(tmpArr);
tmpArr = NULL;
return result;
}
oc实现
- (NSArray *)countingSort:(NSArray *)arr max:(int)maxNum {//[@1,@20,@5]
NSMutableArray *mutableArr = @[].mutableCopy;
NSMutableArray *result = @[].mutableCopy;
//初始化
for (int i = 0; i<=maxNum; i++) { //K
mutableArr[i] = @0;
}
//下标数值++
for (int j = 0; j<arr.count; j++) { // N
int t = [arr[j] intValue];
mutableArr[t] = [NSNumber numberWithInt:[mutableArr[t] intValue]+1];
}
for (int i = 0; i<mutableArr.count; i++) {
NSNumber *tmp = mutableArr[i];
int t = tmp.intValue;
while (t) {
[result addObject:@(i)];
t--;
}
}
return result.copy;
}
Swift 实现
func countingSort(arr : Array<Int>,count:Int,max:Int) -> Array<Int> {
var tmp = 0
var tmpArr = Array.init(repeating: 0, count: max)
var result = Array.init(repeating: 0, count: count)
for i in 0..<arr.count {
tmpArr[arr[i]] += 1
}
for j in 0..<tmpArr.count {
while tmpArr[j] > 0 {
result[tmp] = j
tmpArr[j] -= 1
tmp+=1
}
}
return result
}
以下代码来源于网络,未验证
js 实现
function countingSort(arr, maxValue) {
var bucket = new Array(maxValue+1),
sortedIndex = 0;
arrLen = arr.length,
bucketLen = maxValue + 1;
for (var i = 0; i < arrLen; i++) {
if (!bucket[arr[i]]) {
bucket[arr[i]] = 0;
}
bucket[arr[i]]++;
}
for (var j = 0; j < bucketLen; j++) {
while(bucket[j] > 0) {
arr[sortedIndex++] = j;
bucket[j]--;
}
}
return arr;
}
Python 代码实现
def countingSort(arr, maxValue):
bucketLen = maxValue+1
bucket = [0]*bucketLen
sortedIndex =0
arrLen = len(arr)
for i in range(arrLen):
if not bucket[arr[i]]:
bucket[arr[i]]=0
bucket[arr[i]]+=1
for j in range(bucketLen):
while bucket[j]>0:
arr[sortedIndex] = j
sortedIndex+=1
bucket[j]-=1
return arr
Go 代码实现
func countingSort(arr []int, maxValue int) []int {
bucketLen := maxValue + 1
bucket := make([]int, bucketLen) // 初始为0的数组
sortedIndex := 0
length := len(arr)
for i := 0; i < length; i++ {
bucket[arr[i]] += 1
}
for j := 0; j < bucketLen; j++ {
for bucket[j] > 0 {
arr[sortedIndex] = j
sortedIndex += 1
bucket[j] -= 1
}
}
return arr
}
Java 代码实现
public class CountingSort implements IArraySort {
@Override
public int[] sort(int[] sourceArray) throws Exception {
// 对 arr 进行拷贝,不改变参数内容
int[] arr = Arrays.copyOf(sourceArray, sourceArray.length);
int maxValue = getMaxValue(arr);
return countingSort(arr, maxValue);
}
private int[] countingSort(int[] arr, int maxValue) {
int bucketLen = maxValue + 1;
int[] bucket = new int[bucketLen];
for (int value : arr) {
bucket[value]++;
}
int sortedIndex = 0;
for (int j = 0; j < bucketLen; j++) {
while (bucket[j] > 0) {
arr[sortedIndex++] = j;
bucket[j]--;
}
}
return arr;
}
private int getMaxValue(int[] arr) {
int maxValue = arr[0];
for (int value : arr) {
if (maxValue < value) {
maxValue = value;
}
}
return maxValue;
}
}
网友评论