美文网首页
HashMap学习【1】

HashMap学习【1】

作者: 河神 | 来源:发表于2019-01-05 17:55 被阅读0次

    HashMap的构造函数

    综述

    hashmap是一个数组+链表+红黑树组成的数据结构,数组索引为key的hash值的对应位置,而hash值重复的元素,在元素数量小于8的时候,数据结构为链表,在元素大于8的时候,数据结果为红黑树,因为红黑树的搜索时间复杂度为logn,而链表的搜索时间复杂度为n/2。

    1. 默认构造函数
        /**
         * Constructs an empty <tt>HashMap</tt> with the default initial capacity
         * (16) and the default load factor (0.75).
         */
        public HashMap() {
            this.loadFactor = DEFAULT_LOAD_FACTOR; // all other fields defaulted
        }
    

    使用默认的参数,既使用 0.75 的扩容因子,16的初始容量创建一个空的HashMap.

    2. 指定初始容量和扩容因子的构造函数
        public HashMap(int initialCapacity, float loadFactor) {
           //初始容量不能小于0 
           if (initialCapacity < 0)
                throw new IllegalArgumentException("Illegal initial capacity: " +
                                                   initialCapacity);
            //默认最大容量为 1<<30  既2的30次方,如果大于此数据,则设为最大容量
            if (initialCapacity > MAXIMUM_CAPACITY)
                initialCapacity = MAXIMUM_CAPACITY;
            if (loadFactor <= 0 || Float.isNaN(loadFactor))
                throw new IllegalArgumentException("Illegal load factor: " +
                                                   loadFactor);
            this.loadFactor = loadFactor;
             //这里设置的初始容量并不是直接扩容,而是下一次应该扩容的大小
            this.threshold = tableSizeFor(initialCapacity);
        }
    
    2.1 tableSizeFor()方法
    • 因为HashTable的容量都为2的幂次方,所以这个方法核心就是将初始容量处理,得到比2的幂次方小或相等的数值,并且这个值不能大于最大容量。
    • 因为2的幂次方书都为,1为最高为,其他位都为0,所以这个这个方法的核心是让某数的二进制的所有位都变为1,这样在其最后结果加1就得到了恰好可以覆盖初始容量的值,而在前面减去1是为了防止其恰好为2的幂次方。
         //map的最大容量
        static final int MAXIMUM_CAPACITY = 1 << 30;
    
        /**
         * Returns a power of two size for the given target capacity.
         */
        static final int tableSizeFor(int cap) {
            int n = cap - 1;
            n |= n >>> 1;
            n |= n >>> 2;
            n |= n >>> 4;
            n |= n >>> 8;
            n |= n >>> 16;
            return (n < 0) ? 1 : (n >= MAXIMUM_CAPACITY) ? MAXIMUM_CAPACITY : n + 1;
        }
    

    比如:输入5
    0101 => 0010 | 0101 => 0111
    0111+1=7+1 =8

    3.HashMap的put()方法
    3.1 put方法
        public V put(K key, V value) {
            return putVal(hash(key), key, value, false, true);
        }
    
    3.2 hash(key)方法
    • 在其本身的hash值基础上,将其本身的hash值向右移动16位,与本身的hash值做异或运算,既高16位不变,第16位做异或计算。
        static final int hash(Object key) {
            int h;
            return (key == null) ? 0 : (h = key.hashCode()) ^ (h >>> 16);
        }
    
    3.2 putVal()方法
    • onlyIfAbsent 参数位true的时候,则不改变现有值
    • evict 表处于创建模式,不明白
      1. 当table数组为空或者table数组大小为0的时候,执行resize()方法;
        /**
         * Implements Map.put and related methods
         *
         * @param hash hash for key
         * @param key the key
         * @param value the value to put
         * @param onlyIfAbsent if true, don't change existing value
         * @param evict if false, the table is in creation mode.
         * @return previous value, or null if none
         */
        final V putVal(int hash, K key, V value, boolean onlyIfAbsent,
                       boolean evict) {
            Node<K,V>[] tab;
            Node<K,V> p;
            int n, i;
            if ((tab = table) == null || (n = tab.length) == 0)
                n = (tab = resize()).length;
            if ((p = tab[i = (n - 1) & hash]) == null)
                tab[i] = newNode(hash, key, value, null);
            else {
                Node<K,V> e; K k;
                if (p.hash == hash &&
                    ((k = p.key) == key || (key != null && key.equals(k))))
                    e = p;
                else if (p instanceof TreeNode)
                    e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
                else {
                    for (int binCount = 0; ; ++binCount) {
                        if ((e = p.next) == null) {
                            p.next = newNode(hash, key, value, null);
                            if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st
                                treeifyBin(tab, hash);
                            break;
                        }
                        if (e.hash == hash &&
                            ((k = e.key) == key || (key != null && key.equals(k))))
                            break;
                        p = e;
                    }
                }
                if (e != null) { // existing mapping for key
                    V oldValue = e.value;
                    if (!onlyIfAbsent || oldValue == null)
                        e.value = value;
                    afterNodeAccess(e);
                    return oldValue;
                }
            }
            ++modCount;
            if (++size > threshold)
                resize();
            afterNodeInsertion(evict);
            return null;
        }
    
    3.3 resize()方法
    • 作用:初始化或者加倍table的容量,如果为空,则使用threshold(构造函数中可以设置)字段存储的值进行初始化。如果表不为null,由于我们使用2的幂来扩容,则每个bin元素要么还是在原来的bucket中,要么在2的幂中。
    • 过程:
       /**
         * Initializes or doubles table size.  If null, allocates in
         * accord with initial capacity target held in field threshold.
         * Otherwise, because we are using power-of-two expansion, the
         * elements from each bin must either stay at same index, or move
         * with a power of two offset in the new table.
         *
         * @return the table
         */
        final Node<K,V>[] resize() {
            Node<K,V>[] oldTab = table;
            int oldCap = (oldTab == null) ? 0 : oldTab.length;
            int oldThr = threshold;
            int newCap, newThr = 0;
            //如果老的table容量大于0
            if (oldCap > 0) {
                //如果老的大于等于HashMap最大允许容量,则直接threshold设为最大int数,直接返回老的table,
                if (oldCap >= MAXIMUM_CAPACITY) {
                    threshold = Integer.MAX_VALUE;
                    return oldTab;
                }
                //如果扩容后的cap值比最大容量小,并且老的cap值大于16,则可以将threshold值也同样扩大2倍
                //因为threshold=capacity*loadFactor
                else if ((newCap = oldCap << 1) < MAXIMUM_CAPACITY &&
                         oldCap >= DEFAULT_INITIAL_CAPACITY)
                    newThr = oldThr << 1; // double threshold
            }
            else if (oldThr > 0) // initial capacity was placed in threshold
                newCap = oldThr;
            else {               // zero initial threshold signifies using defaults
                newCap = DEFAULT_INITIAL_CAPACITY;
                newThr = (int)(DEFAULT_LOAD_FACTOR * DEFAULT_INITIAL_CAPACITY);
            }
            if (newThr == 0) {
                float ft = (float)newCap * loadFactor;
                newThr = (newCap < MAXIMUM_CAPACITY && ft < (float)MAXIMUM_CAPACITY ?
                          (int)ft : Integer.MAX_VALUE);
            }
            threshold = newThr;
            @SuppressWarnings({"rawtypes","unchecked"})
                Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap];
            table = newTab;
            if (oldTab != null) {
                for (int j = 0; j < oldCap; ++j) {
                    Node<K,V> e;
                    if ((e = oldTab[j]) != null) {
                        oldTab[j] = null;
                        if (e.next == null)
                            newTab[e.hash & (newCap - 1)] = e;
                        else if (e instanceof TreeNode)
                            ((TreeNode<K,V>)e).split(this, newTab, j, oldCap);
                        else { // preserve order
                            Node<K,V> loHead = null, loTail = null;
                            Node<K,V> hiHead = null, hiTail = null;
                            Node<K,V> next;
                            do {
                                next = e.next;
                                if ((e.hash & oldCap) == 0) {
                                    if (loTail == null)
                                        loHead = e;
                                    else
                                        loTail.next = e;
                                    loTail = e;
                                }
                                else {
                                    if (hiTail == null)
                                        hiHead = e;
                                    else
                                        hiTail.next = e;
                                    hiTail = e;
                                }
                            } while ((e = next) != null);
                            if (loTail != null) {
                                loTail.next = null;
                                newTab[j] = loHead;
                            }
                            if (hiTail != null) {
                                hiTail.next = null;
                                newTab[j + oldCap] = hiHead;
                            }
                        }
                    }
                }
            }
            return newTab;
        }
    

    参考:

    地址
    map容量为何是1<<30 https://blog.csdn.net/qq_33666602/article/details/80139620
    map的tableSizeFor方法 https://blog.csdn.net/fan2012huan/article/details/51097331

    相关文章

      网友评论

          本文标题:HashMap学习【1】

          本文链接:https://www.haomeiwen.com/subject/fbhdrqtx.html