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Problem 10

Problem 10

作者: guanjianhe | 来源:发表于2018-08-05 22:54 被阅读0次
    The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17.
    
    Find the sum of all the primes below two million.
    
    #include <stdio.h>
    
    #define NUM 2000000
    
    int main()
    {
        int i, j;
        unsigned long int sum = 2;
        char arr[NUM] = { 0 };
        
        for ( i = 3; i < NUM; i+=2 )
        {
            if ( 0 == arr[i] )
            {
                sum += i;
                for ( j = 2; i*j < NUM; j++ )
                {
                    arr[i * j] = 1;
                }
            }
        }
        printf( "%ld\n", sum );
        return(0);
    }
    

    解出答案是:142913828922

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