【py小甲鱼笔记】-[课后作业] 第030讲：文件系统：介绍一个

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解答第0题：

import os
dict1 = dict()
style = []
all = os.listdir()
#print(all)
dict1['dir'] = 0
for i in all:
    if os.path.isdir(i):
        dict1['dir'] += 1
    else:
        a = os.path.splitext(i)[1]
        if a not in style:
            style.append(a)
            dict1[a] = 1
        else:
            dict1[a] += 1

print(style)   #['.txt', '.docx', '.png', '.pkl', '.py']
print(dict1)   #{'dir': 2, '.txt': 2, '.docx': 1, '.png': 1, '.pkl': 2, '.py': 1}

解答第1题：

dict1 = dict()
all = os.listdir()
# print(all)
for i in all:
    if os.path.isfile(i):
        dict1[i] = os.path.getsize(i)

print(dict1)   
#{'1.txt': 9, '2.txt': 6, '3.docx': 0, '4.png': 0, '5.pkl': 0, '6.pkl': 0, 'P82.py': 618}

解答第2题：

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fold = "D:\\工作\\201804_学习\\Python\\小甲鱼\\P8\\2-OS"
filename = "test.txt"


def search(fold, filename):
    os.chdir(fold)
    all = os.listdir()
    if os.path.exists(filename):
        print(fold + os.sep + filename)

    for i in all:
        if os.path.isdir(i):
            fold1 = os.path.join(fold, i)
            search(fold1, filename)


search(fold,filename)

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解答第3题：

fold = "D:\\工作\\201804_学习\\Python\\小甲鱼\\P8\\2-OS"
def search(fold,move):
    os.chdir(fold)
    all = os.listdir()
    for i in all:
        if os.path.splitext(i)[1] in move:
            filelist.append(fold + os.sep + i)
            # print(fold + os.sep + i)
        if os.path.isdir(i):
            fold1 = os.path.join(fold, i)
            search(fold1, move)
            os.chdir(fold)
    return filelist
move = [".mp4",".rmvb",".avi"]
filelist = []
a = search(fold,move)
print(a)

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