Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
The solution set must not contain duplicate triplets.
Example:
Given array nums = [-1, 0, 1, 2, -1, -4],
A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]
Solution
class Solution {
public List<List<Integer>> threeSum(int[] nums) {
Arrays.sort(nums); //排序
List<List<Integer>> result = new ArrayList<>();
for (int i = 0; i < nums.length - 2; i++){
if (i > 0 && nums[i] == nums[i-1]) continue; //跳过重复答案
int j = i + 1;
int k = nums.length - 1;
int target = -nums[i];
while (j < k){
int sum = nums[j] + nums[k];
if (sum == target){
result.add(Arrays.asList(nums[i], nums[j], nums[k]));
j++;
k--;
while (j < k && nums[j] == nums[j-1]) j++; //跳过重复答案
while (j < k && nums[k] == nums[k+1]) k--; //跳过重复答案
}else if (sum > target){
k--;
}else if (sum < target){
j++;
}
}
}
return result;
}
}
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