from collections import Counter
skuPurchaseCount = [3, 8, 3, 10, 3, 3, 1, 3, 7, 6, 1, 2, 7, 0, 7, 9, 1, 5, 1, 0]
Counter(skuPurchaseCount).most_common()
# 仅仅一行代码,便输出统计计数结果,并且是一个按照次数统计出来的由大到小排序好的tuples列表
# [(3, 5),(1, 4),(7, 3),(0, 2),(8, 1),(10, 1),(6, 1),(2, 1),(9, 1),(5, 1)]
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