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代码随想录算法训练营第18天|二叉树part05

代码随想录算法训练营第18天|二叉树part05

作者: pangzhaojie | 来源:发表于2023-05-27 11:05 被阅读0次

    二叉树左下角的值

    题目链接

    https://programmercarl.com/0513.%E6%89%BE%E6%A0%91%E5%B7%A6%E4%B8%8B%E8%A7%92%E7%9A%84%E5%80%BC.html

    思路

    递归法,需要回溯深度,只有深度最大值有变化时才会记录左下角

        private int maxDepth = 0;
    private int res = 0;
    public int findBottomLeftValue(TreeNode root) {
        
         find(root, 1);
         return res;
    }
    
    public void find(TreeNode node, int depth) {
        if(node.left == null && node.right == null) {
            if(depth > maxDepth) {
                maxDepth = depth;
                res =  node.val;
            }
        }
        if(node.left != null) {
            find(node.left, depth + 1);
        }
        if(node.right != null) {
        find(node.right, depth + 1);
    
        }
        
    }
    

    路径总和

    题目链接

    https://programmercarl.com/0112.%E8%B7%AF%E5%BE%84%E6%80%BB%E5%92%8C.html

    思路

        private boolean hasPathSum =false;
    public boolean hasPathSum(TreeNode root, int targetSum) {
        if(root == null) {
            return false;
        }
        hasPathSu(root, targetSum);
        return hasPathSum;
    
    }
    
    private void hasPathSu(TreeNode node, int targetSum) {
        if(node.left == null && node.right == null) {
            if(!hasPathSum) {
                hasPathSum = targetSum == node.val;
            }
        }
        if(node.left!= null) {
            hasPathSu(node.left, targetSum - node.val);
        }
        if(node.right != null) {
            hasPathSu(node.right, targetSum - node.val);
        }
    }
    
    
        private List<List<Integer>> res = new ArrayList();
    private List<Integer> path = new ArrayList();
    
        public List<List<Integer>> pathSum(TreeNode root, int targetSum) {
            if(root ==null) {
                return res;
            }
            pathSum1(root, targetSum);
            return res;
        }
    
        private void pathSum1(TreeNode root, int targetSum) {
            path.add(root.val);
            if(root.left == null && root.right == null) {
                if(root.val == targetSum) {
                    res.add(new ArrayList<>(path));
                }
            }
            if(root.left != null) {
                pathSum1(root.left, targetSum - root.val);
                path.remove(path.size() - 1);
            }
            if(root.right != null) {
                pathSum1(root.right, targetSum - root.val);
                path.remove(path.size() - 1);
    
            }
        }
    

    构造二叉树

    思路挺简单的,记住区间左闭右开 保持这一原则

        private Map<Integer, Integer> map = new HashMap();
    public TreeNode buildTree(int[] inorder, int[] postorder) {
        for(int i = 0; i < inorder.length; i++) {
            map.put(inorder[i], i);
        }
        return buildTree1(inorder, 0, inorder.length, postorder, 0, postorder.length);
    }
    
    private TreeNode buildTree1(int[] inorder, int inBegin, int inEnd, int[] postorder, int poBegin, int poEnd) {
        if(inBegin == inEnd) {
            return null;
        }
        int mid = map.get(postorder[poEnd - 1]);
        TreeNode root = new TreeNode(inorder[mid]);
        root.left = buildTree1(inorder, inBegin, mid, postorder, poBegin, poBegin + mid - inBegin);
        root.right = buildTree1(inorder, mid+1, inEnd, postorder, poBegin + mid - inBegin, poEnd-1);
        return root;
    }

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