[LeetCode]94. Binary Tree Inorde

Given a binary tree, return the inorder traversal of its nodes' values.

For example:
Given binary tree [1,null,2,3],

  1 
   \ 
    2
   / 
  3

return [1,3,2].

Note: Recursive solution is trivial, could you do it iteratively?

中序遍历

中序遍历是首先遍历左子树，然后访问根结点，最后遍历右子树。在遍历左、右子树时，仍然先遍历左子树，再访问根结点，最后遍历右子树。在遍历上图[1,2,3]组成的二叉树时，遍历结果为[1,3,2]

方法

中序遍历二叉树，如果不用递归的方式，同样需要借助栈。
将当前节点压栈，然后将当前节点指向左子节点压栈，循环直至左节点为空。然后从栈里取出节点，同时取出节点值。然后将当前节点指向右子节点，若当前节点不为空，循环开始的过程。直至当前节点为空并且栈为空的时候，退出循环。

c代码

#include <assert.h>
#include <stdlib.h>

struct TreeNode {
    int val;
    struct TreeNode *left;
    struct TreeNode *right;
};

/**
 * Return an array of size *returnSize.
 * Note: The returned array must be malloced, assume caller calls free().
 */
int* inorderTraversal(struct TreeNode* root, int* returnSize) {
    struct TreeNode* node;
    struct TreeNode** nodes = (struct TreeNode **)malloc(sizeof(struct TreeNode *) * 1000);
    node = root;
    int nodesTop = 0;
    int* vals = (int *)malloc(sizeof(int) * 1000);
    int valsTop = 0;
    while(node!=NULL || nodesTop!=0) {
        while(node != NULL) {
            nodes[nodesTop++] = node;
            node = node->left;
        }
        node = nodes[--nodesTop];
        vals[valsTop++] = node->val;
        node = node->right;
    }
    *returnSize = valsTop;
    return vals;
}

int main() {
    struct TreeNode* root = (struct TreeNode *)malloc(sizeof(struct TreeNode));
    root->val = 1;
    struct TreeNode* node1_2 = (struct TreeNode *)malloc(sizeof(struct TreeNode));
    node1_2->val = 2;
    root->left = NULL;
    root->right = node1_2;
    struct TreeNode* node2_3 = (struct TreeNode *)malloc(sizeof(struct TreeNode));
    node2_3->val = 3;
    node1_2->left = node2_3;
    node1_2->right = NULL;
    node2_3->left = NULL;
    node2_3->right = NULL;

    int returnSize = 0;
    int* vals = inorderTraversal(root, &returnSize);
    assert(returnSize == 3);
    assert(vals[0] == 1);
    assert(vals[1] == 3);
    assert(vals[2] == 2);

    return 0;
}

扩展

前序遍历二叉树
[LeetCode]144. Binary Tree Preorder Traversal