常用SQL 50条

作者: 不怕天黑_0819 | 来源:发表于2022-03-08 11:09 被阅读0次

    有如下四张表:根据四张表的数据组合各种场景的查询语句:

    Student(Sid,Sname,Sage,Ssex)学生表
    Sid:学号
    Sname:学生姓名
    Sage:学生年龄
    Ssex:学生性别
    
    Course(Cid,Cname,T#)课程表
    Cid:课程编号
    Cname:课程名称
    Tid:教师编号
    
    SC(Sid,Cid,score)成绩表
    Sid:学号
    Cid:课程编号
    score:成绩
    
    Teacher(Tid,Tname)教师表
    Tid:教师编号:
    Tname:教师名字
    

    1、查询“001”课程比“002”课程成绩高的所有学生的学号

    select a.sid from 
    (select sid,score from sc where cid='001')a,
    (select sid,score from sc where cid='002')b 
    where a.sid = b.sid and a.score>b.score;
    

    2、查询平均成绩大于60分的同学的学号和平均成绩

    group by sid 
    having avg(score)>60;
    

    3、查询所有同学的学号、姓名、选课数、总成绩

    sum_score  as 总成绩
    from student s
    left join 
    (select sid,count(cid) as count_cid,sum(score) as sum_score 
    from sc group by sid )sc
    on s.sid = sc.sid;
    

    4、查询姓‘李’的老师的个数:

    from teacher 
    where tname like '李%';
    

    5、查询没有学过“叶平”老师可的同学的学号、姓名:

    select s.sid,s.sname 
    from student as s 
    where s.sid not in (
        select DISTINCT sid 
        from sc as sc 
        where sc.cid in (
            select cid 
            from course as c 
            left join teacher as t on c.tid = t.tid 
            where t.tname = '叶平')
    );
    

    6、查询学过“叶平”老师所教的所有课的同学的学号、姓名:

    select s.sid,s.sname 
    from student as s 
    where s.sid in (
        select distinct sc.sid 
      from sc as sc 
      where sc.cid in (
        select cid 
        from course as c 
        left join teacher as t on c.tid = t.tid 
        where t.tname = '叶平')
            group by sc.sid 
        HAVING count(cid)=
        (select count(cid) 
         from course as c left join teacher as t on c.tid = t.tid 
         where t.tname = '叶平')
    );
    

    7、查询学过“011”并且也学过编号“002”课程的同学的学号、姓名:

    SELECT s.sid,s.sname 
    from student as s 
    left join sc as sc on s.sid = sc.sid
    where sc.cid = '001'
    and EXISTS(
      select * from sc as sc_2 
      where sc.sid = sc_2.sid 
      and sc_2.cid='002');
    
    select s.sid,s.sname
    from student as s 
    left join sc as sc 
    on sc.sid = s.sid
    where sc.cid = '001'
    and s.sid in (
      select sid from sc as sc_2 
      where sc_2.cid='002' 
      and sc_2.sid = sc.sid);
    

    8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名:

    select sid,sname
    from (select student.sid,student.sname,score,
         (select score from sc as sc_2 
          where sc_2.sid = student.sid 
          and sc_2.cid = '002') as score2 
          from student,sc 
          where student.sid=sc.sid and cid = '001') s_2
    where score2<score;
    

    9、查询所有课程成绩小于60的同学的学号、姓名:

    select sid,sname
    from student
    where sid not in 
    (select s.sid 
    from student s,sc 
    where s.sid=sc.sid and score>60 );
    
    select sid,sname
    from student s
    where not EXISTS (
    select s.sid from sc 
    where sc.sid = s.sid and sc.score>60);
    

    10、查询没有学全所有课的同学的学号、姓名:

    select s.sid,s.sname
    from student s ,sc sc 
    where s.sid = sc.sid
    group by s.sid,s.sname
    having count(sc.cid)<(
    select count(cid) 
    from course);
    
    select s.sid,s.sname
    from student s 
    right join sc sc on s.sid = sc.sid
    group by s.sid,s.sname
    having count(sc.cid)<
    (select count(cid) from course);
    

    11、查询至少有一门课与学号为“1001”同学所学相同的同学的学号和姓名:

    select student.sid,sname
    from student,sc 
    where student.sid = sc.sid
    and cid in 
    (select cid from sc where sid='1001');
    
    select s.sid,s.sname
    from sc sc left join student as s
    on sc.sid = s.sid
    where sc.cid in (select cid from sc where sid='1001');
    
    select sc_1.sid,s.sname
    from sc sc_1 left join student as s
    on sc_1.sid = s.sid
    where 
    exists (select sc_2.cid from sc as sc_2 
    where sc_1.cid = sc_2.cid 
    and sc_2.sid = '1001');
    

    12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名;
    13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩:

    update sc set score = 
    (select avg(sc_2.score) from sc sc_2  
    where sc_2.cid = sc.cid)
    where cid in 
    (select c.cid from course c 
    left join teacher t on t.tid = c.tid 
    where t.tname = '叶平');
    

    14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名:

    select sc_1.sid 
    from (select cid from sc where sid='1002')a
    left join sc sc_1 on a.cid = sc_1.cid
    where sc_1.sid<>'1002' 
    group by sc_1.sid 
    having count(sc_1.cid) = 
    (select count(cid) from sc where sid='1002');
    
    select a.sid,s.sname from 
    (select sid,GROUP_CONCAT(cid order by cid separator ',') as cid_str 
    from sc where sid='1002')b,
    (select sid,GROUP_CONCAT(cid order by cid separator ',') as cid_str 
    from sc group by sid)a
    left join student s 
    on a.sid = s.sid
    where a.cid_str = b.cid_str and a.sid<>'1002';
    

    15、删除学习“叶平”老师课的SC表记录:

    delete from sc WHERE
    cid in (
    select c.cid from course c 
    LEFT JOIN teacher t on c.tid=t.tid 
    where t.tname = '叶平');
    

    16、向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、002号课的平均成绩:

    (select avg(score) from sc where cid='0022')
    from student 
    where sid not in (select sid from sc where cid='002');
    

    17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示:学生ID,数据库,企业管理,英语,有效课程数,有效平均分:

    select sid as 学生id,
    (SELECT score from sc 
    where sc.sid = t.sid and cid='004') as 数据库,
    (select score from sc 
    where sc.sid = t.sid and cid='001') as 企业管理,
    (select score from sc 
    where sc.sid = t.sid and cid='015') as 英语,
    count(cid) as 有效课程数, avg(t.score) as 平均成绩
    from sc as t 
    group by sid
    order by avg(t.score);
    

    18、查询各科成绩最高和最低的分:以如下的形式显示:课程ID,最高分,最低分

    select l.cid as 课程id,l.score as 最高分,
    r.score as 最低分
    from sc l,sc r
    where l.cid = r.cid
    and l.score = 
    (select max(t.score) from sc t 
    where l.cid = t.cid group by t.cid)
    and r.score = (select min(t.score) from sc t 
    where r.cid = t.cid group by t.cid)
    order by l.cid;
    
    select cid as 课程id,max(score) as 最高分,
    min(score) as 最低分
    from sc 
    group by cid;
    

    19、按各科平均成绩从低到高和及格率的百分数从高到低顺序:

    SELECT t.cid as 课程号,
    c.cname as 课程名,
    COALESCE(avg(score),0) as 平均成绩,
    100*sum(case 
    when COALESCE(score,0)>=60 
    then 1 else 0 END)/count(*) as 及格百分数
    from sc t
    left join course c 
    on t.cid = c.cid
    group by t.cid
    order by 100*sum(case 
    when COALESCE(score,0)>=60 
    then 1 else 0 END)/count(*);
    

    20、查询如下课程平均成绩和及格率的百分数(用”1行”显示): 企业管理(001),马克思(002),OO&UML (003),数据库(004):
    21、查询不同老师所教不同课程平均分从高到低显示:

    t.tname as 教师姓名,
    sc.cid as 课程id,
    avg(score) as 平均成绩
    from sc as sc
    LEFT JOIN course c on sc.cid = c.cid
    left join teacher t on c.tid = t.tid
    group by sc.cid 
    order by avg(sc.score) desc;
    

    22、查询如下课程成绩第3名到第6名的学生成绩单:企业管理(001),马克思(002),UML(003),数据库(004):
    23、统计下列各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ 小于60] :

    sum(case when score between 85 and 100 then 1 else 0 end) as '[100-85]',
    sum(case when score between 70 and 85 then 1 else 0 end) as '[85-70]',
    sum(case when score between 60 and 70 then 1 else 0 end) as '[70-60]',
    sum(case when score<60 then 1 else 0 end) as '[60-0]'
    from sc as sc 
    left join course as c
    on sc.cid = c.cid
    group by sc.cid;
    

    24、查询学生平均成绩及其名次:

    from (select sid,avg(score) as 平均成绩 
    from sc group by sid)t1 
    where 平均成绩>t2.平均成绩) as 名次,
    sid as 学生学号,平均成绩 
    from (select sid,avg(score) 平均成绩 from sc group by sid) as t2
    order by 平均成绩 desc;
    

    25、查询各科成绩前三名的记录(不考虑成绩并列情况):

    from sc sc_1
    where (
    select count(3) from sc sc_2 
    where sc_1.cid = sc_2.cid 
    and sc_2.score>=sc_1.score)<=2 
    order by sc_1.cid
    );
    

    26、查询每门课程被选修的学生数:

    select cid, count(sid)
    from sc 
    group by cid;
    

    27、查询出只选修一门课程的全部学生的学号和姓名:

    select sc.sid,s.sname,
    count(sc.cid) as 课程数
    from sc as sc
    LEFT JOIN student as s
    on sc.sid = s.sid
    group by sc.sid
    having count(sc.cid)=1;
    

    28、查询男生、女生人数:

    select count(ssex) as 男生人数
    from student
    group by ssex
    having ssex = '男';
    select count(2) from student
    where ssex = '女';
    

    29、查询姓“张”的学生名单:

    from student 
    where sname like '张%';
    

    30、查询同名同姓的学生名单,并统计同名人数:

    select sname,count(8)
    from student 
    group by sname
    having count(8)>1;
    

    31、1981年出生的学生名单(注:student表中sage列的类型是datetime):
    32、查询平均成绩大于85的所有学生的学号、姓名和平均成绩:

    select s.sname,sc.sid,avg(sc.score) as 平均成绩
    from sc as sc
    left join student as s 
    on sc.sid = s.sid
    group by sc.sid 
    having avg(sc.score)>85;
    

    33、查询每门课程的平均成绩,结果按平均成绩升序排序,平均成绩相同时,按课程号降序排列:

    select cid,avg(score)
    from sc 
    group by cid
    order by avg(score),cid desc;
    

    34、查询课程名称为“数据库”,且分数低于60的学生名字和分数:

    select c.cname,s.sid,s.sname,sc.score
    from course c
    left join sc on sc.cid = c.cid
    LEFT JOIN student s on s.sid = sc.sid
    where c.cname = '数据库' and sc.score<60;
    

    35、查询所有学生的选课情况:

    select sc.sid,sc.cid,s.sname,c.cname
    from sc 
    LEFT JOIN course c on sc.cid = c.cid
    left join student s on sc.sid = s.sid;
    

    36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数:

    select distinct s.sid,s.sname,sc.cid,sc.score
    from sc 
    left join student s on sc.sid = s.sid
    left join course c on sc.cid = c.cid
    where sc.score>70;
    

    37、查询不及格的课程,并按课程号从大到小的排列:

    select cid
    from sc 
    where score<60
    ORDER BY cid;
    

    38、查询课程编号为“003”且课程成绩在80分以上的学生的学号和姓名:

    select sc.sid,s.sname 
    from sc 
    left join student s on sc.sid = s.sid
    where sc.cid = '003' and sc.score>80;
    

    39、求选了课程的学生人数:

    (select distinct sid from sc)a;
    

    40、查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩:

    from sc sc 
    left join student s on sc.sid = s.sid
    left join course c on sc.cid = c.cid
    left join teacher t on c.tid = t.tid
    where t.tname = '叶平'
    and sc.score = (
    select max(score) 
    from sc sc_1 
    where sc.cid = sc_1.cid);
    

    41、查询各个课程及相应的选修人数:

    select cid,count(*) from sc group by cid;
    42、查询不同课程成绩相同的学生和学号、课程号、学生成绩:
    select DISTINCT a.sid,a.cid,a.score
    from sc as a ,sc as b 
    where a.score = b.score
    and a.cid <> b.cid;
    

    43、查询每门课程成绩最好的前两名:
    44、统计每门课程的学生选修人数(超过10人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排序,若人数相同,按课程号升序排序:

    select cid as 课程号,count(8) as 选修人数
    from sc
    group by cid
    HAVING count(sid)>10
    order by count(8) desc,cid;
    

    45、检索至少选修两门课程的学生学号:

    select sid
    from sc
    group by sid
    having count(8)>=2;
    

    46、查询全部学生选修的课程和课程号和课程名:

    select cid,cname
    from course 
    where cid in (select cid from sc group by cid);
    

    47、查询没学过”叶平”老师讲授的任一门课程的学生姓名:

    from student 
    where sid not in (
        select sid 
        from sc,course,teacher 
        where course.tid = teacher.tid and sc.cid = course.cid 
        and teacher.tname='叶平'
    );
    

    48、查询两门以上不及格课程的同学的学号以及其平均成绩:

    from sc
    where sid in (
        select sid 
        from sc 
        where score<60 
        group by sid 
        having count(8)>2
    )
    group by sid;
    

    49、检索“004”课程分数小于60,按分数降序排列的同学学号:

    from sc
    where cid='004'
    and score<60
    order by score desc;
    

    50、删除“002”同学的“001”课程的成绩:

    where sid = '002'
    and cid = '001';
    

    引用链接:blog.csdn.net/hundan_520520/article/details/54881208

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        本文标题:常用SQL 50条

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