WKWebView打开支付宝客户端

场景描述：
公司的APP主要通过WKWebView调用wap页面，里面有支付宝支付。点击立即支付，如果手机装有支付宝，应该打开支付宝客户端的。问题是，Android截获URL跳转是没有问题的，但是iOS却有问题。无法打开客户端还是停留支付宝wap页面。一直调试考虑如何解决这个问题，还是同事点子多，结合了Android和iOS重新拼接URL，然后open，就可以了，能想到这种法子，实在是佩服。
以下为参考代码：

//在发送请求之前，决定是否跳转  如果不实现这个代理方法,默认会屏蔽掉打电话等url
- (void)webView:(WKWebView *)webView decidePolicyForNavigationAction:(WKNavigationAction *)navigationAction decisionHandler:(void (^)(WKNavigationActionPolicy))decisionHandler{
  NSString *url = [navigationAction.request.URL.absoluteString stringByRemovingPercentEncoding];
    NSString* reUrl=[[webView URL] absoluteString];
    if ([url containsString:kBaseUrl]) {
        reUrl=url;
    }
    
    if ([url containsString:@"alipay://"]) {
        //        alipay://alipayclient/?{"dataString":"h5_route_token=\"5ca0bf28bad7cdb27e9069853cfb67d7\"&is_h5_route=\"true\"","requestType":"SafePay","fromAppUrlScheme":"alipays"}
        NSString* dataStr=[url substringFromIndex:23];
        NSLog(@"%@",dataStr);
        NSDictionary *dict = [NSJSONSerialization JSONObjectWithData:[dataStr dataUsingEncoding:NSUTF8StringEncoding] options:kNilOptions error:nil];
        //appId=20000125&orderSuffix=h5_route_token%3D%22ba8f51bce235fe3b02f945da619125e5%22%26is_h5_route%3D%22true%22#Intent
        NSMutableString* mString=[[NSMutableString alloc] init];
        [mString appendString:@"alipays://platformapi/startApp?appId=20000125&orderSuffix="];
        //        [mString appendString:@"alipay://alipayclient/?appId=20000125&orderSuffix="];
      //url进行编码
        [mString appendString:[self encodeString:dict[@"dataString"]]];
        //        alipays://platformapi/startApp?appId=20000125&orderSuffix=h5_route_token=\"5f941ada4bcb49832562e7289dce72ee\"&is_h5_route=\"true\""
        
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:mString]];
        decisionHandler(WKNavigationActionPolicyAllow);
        return;
    }
}

-(NSString*)encodeString:(NSString*)unencodedString{
    
    // CharactersToBeEscaped = @":/?&=;+!@#$()~',*";
    
    // CharactersToLeaveUnescaped = @"[].";
    
    NSString *encodedString = (NSString *)
    
    CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,
                                                              
                                                              (CFStringRef)unencodedString,
                                                              
                                                              NULL,
                                                              
                                                              (CFStringRef)@"!*'();:@&=+$,/?%#[]",
                                                              
                                                              kCFStringEncodingUTF8));
    
    return encodedString;
    
}

虽然可以打开测试没有问题，但是还是觉得可能会有其他问题，如果哪位兄弟姐妹遇到过类似问题，希望指教。

后来又尝试通过iOS返回的URL，但是对参数进行编码，也可以，提出疑问，为啥iOS本身的URL或者用Android的URL都可以打开iOS端的支付宝：

- (void)webView:(WKWebView *)webView decidePolicyForNavigationAction:(WKNavigationAction *)navigationAction decisionHandler:(void (^)(WKNavigationActionPolicy))decisionHandler{

    NSString *url = [navigationAction.request.URL.absoluteString stringByRemovingPercentEncoding];
    NSString* reUrl=[[webView URL] absoluteString];
    if ([url containsString:kBaseUrl]) {
        reUrl=url;
    }
    
    if ([url containsString:@"alipay://"]) {
 NSInteger subIndex = 23;
        NSString* dataStr=[url substringFromIndex:subIndex];
        //编码
        NSString *encodeString = [self encodeString:dataStr];
        NSMutableString* mString=[[NSMutableString alloc] init];
        [mString appendString:[url substringToIndex:subIndex]];
        [mString appendString:encodeString];
        
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:mString]];
        decisionHandler(WKNavigationActionPolicyAllow);
        return;
    }