SQL JOINS

作者: 惜时流光沿途留殇 | 来源:发表于2019-08-17 23:32 被阅读0次

示意图

sql join.png

事前准备

create table Table_A(id int,value VARCHAR(50));
create table Table_B(id int,value VARCHAR(50));
insert Table_A VALUES(1,'FOX');
insert Table_A VALUES(2,'COP');
insert Table_A VALUES(3,'TAXI');
insert Table_A VALUES(4,'LINCION');
insert Table_A VALUES(5,'ARIZONA');
insert Table_A VALUES(6,'WASHINGTON');
insert Table_A VALUES(7,'DELL');
insert Table_A VALUES(10,'LUCENT');
insert Table_B VALUES(1,'TROT');
insert Table_B VALUES(2,'CAR');
insert Table_B VALUES(3,'CAB');
insert Table_B VALUES(6,'MONUMENT');
insert Table_B VALUES(7,'PC');
insert Table_B VALUES(8,'MICROSOFT');
insert Table_B VALUES(9,'APPLE');
insert Table_B VALUES(11,'SCOTCH');

INNER JOIN (内连接)

INNER_JOIN.png

示例查询

SELECT A.id AS A_PK, B.id AS B_PK,

       A.Value AS A_Value, B.Value AS B_Value

FROM Table_A A

INNER JOIN Table_B B

ON A.id = B.id;

结果如下

+------+------+------------+----------+

| A_PK | B_PK | A_Value    | B_Value  |

+------+------+------------+----------+

|    1 |    1 | FOX        | TROT     |

|    2 |    2 | COP        | CAR      |

|    3 |    3 | TAXI       | CAB      |

|    6 |    6 | WASHINGTON | MONUMENT |

|    7 |    7 | DELL       | PC       |

+------+------+------------+----------+

5 rows in set (0.00 sec)

LEFT JOIN (左连接)

LEFT_JOIN.png
SELECT A.id AS A_PK, B.id AS B_PK,

       A.Value AS A_Value, B.Value AS B_Value

FROM Table_A A

LEFT JOIN Table_B B

ON A.id = B.id;

结果如下

+------+------+------------+----------+

| A_PK | B_PK | A_Value    | B_Value  |

+------+------+------------+----------+

|    1 |    1 | FOX        | TROT     |

|    2 |    2 | COP        | CAR      |

|    3 |    3 | TAXI       | CAB      |

|    4 | NULL | LINCION    | NULL     |

|    5 | NULL | ARIZONA    | NULL     |

|    6 |    6 | WASHINGTON | MONUMENT |

|    7 |    7 | DELL       | PC       |

|   10 | NULL | LUCENT     | NULL     |

+------+------+------------+----------+

8 rows in set (0.00 sec)

RIGHT JOIN (右连接)

RIGHT_JOIN.png
SELECT A.id AS A_PK, B.id AS B_PK,

       A.Value AS A_Value, B.Value AS B_Value

FROM Table_A A

RIGHT  JOIN Table_B B

ON A.id = B.id;

结果如下

+------+------+------------+----------+

+------+------+------------+-----------+

| A_PK | B_PK | A_Value    | B_Value   |

+------+------+------------+-----------+

|    1 |    1 | FOX        | TROT      |

|    2 |    2 | COP        | CAR       |

|    3 |    3 | TAXI       | CAB       |

|    6 |    6 | WASHINGTON | MONUMENT  |

|    7 |    7 | DELL       | PC        |

| NULL |    8 | NULL       | MICROSOFT |

| NULL |    9 | NULL       | APPLE     |

| NULL |   11 | NULL       | SCOTCH    |

+------+------+------------+-----------+

8 rows in set (0.00 sec)

OUTER JOIN (外连接)

FULL_OUTER_JOIN.png
SELECT A.id AS A_PK, B.id AS B_PK,

       A.Value AS A_Value, B.Value AS B_Value

FROM Table_A A

OUTER  JOIN Table_B B

ON A.id = B.id;

结果如下

ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FULL OUTER JOIN Table_B B

ON A.PK = B.PK' at line 4

注:我当前示例使用的 MySQL 不支持FULL OUTER JOIN。
应当返回的结果(使用 UNION 模拟):

SELECT Table_A.id AS A_PK, Table_B.id AS B_PK,

Table_A.Value AS A_Value, Table_B.Value AS B_Value

FROM

    Table_A

LEFT JOIN Table_B ON Table_A.id = Table_B.id

UNION ALL

    SELECT

        Table_A.id AS A_PK, Table_B.id AS B_PK,

Table_A.Value AS A_Value, Table_B.Value AS B_Value

    FROM

        Table_A

    RIGHT JOIN Table_B ON Table_A.id = Table_B.id;
+------+------------+------+-----------+

| PK   | Value      | PK   | Value     |

+------+------------+------+-----------+

|    1 | FOX        |    1 | TROT      |

|    2 | COP        |    2 | CAR       |

|    3 | TAXI       |    3 | CAB       |

|    4 | LINCION    | NULL | NULL      |

|    5 | ARIZONA    | NULL | NULL      |

|    6 | WASHINGTON |    6 | MONUMENT  |

|    7 | DELL       |    7 | PC        |

|   10 | LUCENT     | NULL | NULL      |

| NULL | NULL       |    8 | MICROSOFT |

| NULL | NULL       |    9 | APPLE     |

| NULL | NULL       |   11 | SCOTCH    |

+------+------------+------+-----------+

11 rows in set (0.00 sec)

LEFT EXCULDING JOIN

LEFT_EXCLUDING_JOIN.png
SELECT A.id AS A_PK, B.id AS B_PK,

       A.Value AS A_Value, B.Value AS B_Value

FROM Table_A A

LEFT JOIN Table_B B

ON A.id = B.id

WHERE B.id is null;

结果如下

+------+------+---------+---------+

| A_PK | B_PK | A_Value | B_Value |

+------+------+---------+---------+

|    4 | NULL | LINCION | NULL    |

|    5 | NULL | ARIZONA | NULL    |

|   10 | NULL | LUCENT  | NULL    |

+------+------+---------+---------+

3 rows in set (0.00 sec)

RIGHT EXCULDING JOIN

RIGHT_EXCLUDING_JOIN.png
SELECT A.id AS A_PK, B.id AS B_PK,

       A.Value AS A_Value, B.Value AS B_Value

FROM Table_A A

RIGHT  JOIN Table_B B

ON A.id = B.id

WHERE A.id is null;

结果如下

+------+------+---------+-----------+

| A_PK | B_PK | A_Value | B_Value   |

+------+------+---------+-----------+

| NULL |    8 | NULL    | MICROSOFT |

| NULL |    9 | NULL    | APPLE     |

| NULL |   11 | NULL    | SCOTCH    |

+------+------+---------+-----------+

3 rows in set (0.00 sec)

OUTER EXCULDING JOIN

FULL_OUTER_JOIN.png
SELECT A.id AS A_PK, B.id AS B_PK,

       A.Value AS A_Value, B.Value AS B_Value

FROM Table_A A

FULL OUTER JOIN  Table_B B

ON A.id = B.id

WHERE A.id is null

and B.id is null;

结果如下

ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FULL OUTER JOIN Table_B B

ON A.PK = B.PK

WHERE A.PK IS NULL

OR B.PK IS NULL' at line 4

应当返回的结果(用 UNION 模拟):

SELECT
    Table_A.id AS A_PK,
    Table_B.id AS B_PK,
    Table_A.
VALUE
    AS A_Value,
    Table_B.
VALUE
    AS B_Value
FROM
    Table_A
LEFT JOIN Table_B ON Table_A.id = Table_B.id
WHERE
    Table_B.id IS NULL
UNION ALL
    SELECT
        Table_A.id AS A_PK,
        Table_B.id AS B_PK,
        Table_A.
    VALUE
        AS A_Value,
        Table_B.
    VALUE
        AS B_Value
    FROM
        Table_A
    RIGHT JOIN Table_B ON Table_A.id = Table_B.id
        Table_A.id IS NULL;
+------+---------+------+-----------+

| PK   | Value   | PK   | Value     |

+------+---------+------+-----------+

|    4 | LINCION | NULL | NULL      |

|    5 | ARIZONA | NULL | NULL      |

|   10 | LUCENT  | NULL | NULL      |

| NULL | NULL    |    8 | MICROSOFT |

| NULL | NULL    |    9 | APPLE     |

| NULL | NULL    |   11 | SCOTCH    |

+------+---------+------+-----------+

6 rows in set (0.00 sec)

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