1003 我要通过！ (20 分)

#include<stdio.h>

 

int main(void) {

    int n, k, flag;

    char ch;

    

    scanf("%d", &n);

    getchar();

    while ( n-- ) {

        int a[3] = {0}; 

        k = 0, flag = 1;


        while ( ( ch = getchar() ) != '\n' ) {

            if ( ch == 'A' )    a[k]++;

            else if ( ch == 'P' && k == 0 ) k = 1;

            else if ( ch == 'T' && k == 1 ) k = 2;

            else    flag = 0;  

        }

        if ( flag && k == 2 && a[1] && a[0] * a[1] == a[2] )    printf("YES\n");

        else    printf("NO\n");

    }

    

    return 0;

}