sqlzoo练习13-using NULL

作者: 皮皮大 | 来源:发表于2020-01-31 15:17 被阅读0次

    本文中讲解的是当数据库的表中的数据存在缺失值NULL的时候,该如何进行处理。下面的数据含有两个表teacherdept

    The school includes many departments. Most teachers work exclusively for a single department. Some teachers have no department.

    image

    using null

    练习

    1. List the teachers who have NULL for their department.

    找出dept为空的老师

    select name
    from teacher
    where dept in NULL;   -- 注意不能使用dept=NULL
    
    1. Note the INNER JOIN misses the teachers with no department and the departments with no teacher.

    inner join能够排除老师为空的系或者没有系的老师

    select teacher.name, dept.name
    from teacher
    inner join dept on (teacher.dept=dept.id);
    
    1. Use a different JOIN so that all teachers are listed.
    select teacher.name. dept.name
    from teacher
    full join dept on teacher.dept=dept.id
    where teacher.name is not null;  -- 方法1
    
    select teacher.name, dept.name
    from teacher
    left join dept on teacher.dept=detp.id;  -- 方法2
    
    1. Use a different JOIN so that all departments are listed.
    -- 方法1
    select teacher.name, dept.name
    from dept
    full join teacher on dept.id=teacher.dept
    where dept.name is not null;
    
    -- 方法2
    select teacher.name, dept.name
    from teacher
    right join dept on teacher.dept=detp.id;
    
    1. Use COALESCE to print the mobile number. Use the number '07986 444 2266' if there is no number given. Show teacher name and mobile number or '07986 444 2266'
    select name, coalesce(mobile, '07986 444 2266')
    from teacher
    
    1. Use the COALESCE function and a LEFT JOIN to print the teacher name and department name. Use the string 'None' where there is no department.
    select teacher.name, coalesce(dept.name, 'None')
    from teacher
    left join dept on teacher.dept=dept.id;
    
    1. Use COUNT to show the number of teachers and the number of mobile phones.
    select count(name), count(mobile)
    from teacher;
    
    1. Use COUNT and GROUP BY dept.name to show each department and the number of staff. Use a RIGHT JOIN to ensure that the Engineering department is listed.
    select dept.name, count(teacher.name) 
    from teacher
    right join dept on dept.id=teacher.dept
    group by dept.name;
    
    1. Use CASE to show the name of each teacher followed by 'Sci' if the teacher is in dept 1 or 2 and 'Art' otherwise.
    select teacher.name,
       case when (teacher.dept=1 or teacher.dept=2) then 'Sci'
       else 'Art' end
    from teacher;
    
    1. Use CASE to show the name of each teacher followed by 'Sci' if the teacher is in dept 1 or 2, show 'Art' if the teacher's dept is 3 and 'None' otherwise.
    select teacher.name,
      case when teacher.dept=1 or teacher.dept=2 then 'Sci'
           when teacher.dept=3 then 'Art'
      else 'None' end
    from teacher
    

    About coalesce函数

    COALESCE takes any number of arguments and returns the first value that is not null.

    笔记:取第一个不是NULL值的数据

    image

    About case function

    case表达式的两种写法

    case sex   -- 1. 简单表达式
       when '1' then '男'
       when '2' then '女'
    else 'other' end
    
    case when sex='1' then '男'  -- 2. 搜索表达式
         when sex='2' then '女'
    else 'other' end
    

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