美文网首页Leetcode做题笔记
Leetcode笔记——563. Binary Tree Til

Leetcode笔记——563. Binary Tree Til

作者: Scaryang | 来源:发表于2019-01-06 10:08 被阅读0次

Problem

Given a binary tree, return the tilt of the whole tree.

The tilt of a tree node is defined as the absolute difference between the sum of all left subtree node values and the sum of all right subtree node values. Null node has tilt 0.

The tilt of the whole tree is defined as the sum of all nodes' tilt.

Example

一个例子

Solution

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    int tilt = 0;
    int findTilt(TreeNode* root) {
        traverse(root);
        return tilt;
    }
    
    int traverse(TreeNode* root)
    {
        if (root == NULL) return 0;
        int left = traverse(root->left);
        int right = traverse(root->right);
        tilt += abs(left-right);
        return left+right+root->val;
    }
};

简单的分治的思想就可以解决这个问题。

相关文章

网友评论

    本文标题:Leetcode笔记——563. Binary Tree Til

    本文链接:https://www.haomeiwen.com/subject/jmojrqtx.html