美文网首页
Faster-RCNN如何产生Anchors(generate_

Faster-RCNN如何产生Anchors(generate_

作者: zju_dream | 来源:发表于2019-07-23 10:14 被阅读0次
    #功能描述:生成多尺度、多宽高比的anchors。  
    #          尺度为:128,256,512; 宽高比为:1:2,1:1,2:1  
    
    import numpy as np  #提供矩阵运算功能的库  
    
    #生成anchors总函数:ratios为一个列表,表示宽高比为:1:2,1:1,2:1  
    #2**x表示:2^x,scales:[2^3 2^4 2^5],即:[8 16 32]  
    def generate_anchors(base_size=16, ratios=[0.5, 1, 2],  
                         scales=2**np.arange(3, 6)):  
        """ 
        Generate anchor (reference) windows by enumerating aspect ratios X 
        scales wrt a reference (0, 0, 15, 15) window. 
        """  
        base_anchor = np.array([1, 1, base_size, base_size]) - 1  #新建一个数组:base_anchor:[0 0 15 15]  
        ratio_anchors = _ratio_enum(base_anchor, ratios)  #枚举各种宽高比  
        anchors = np.vstack([_scale_enum(ratio_anchors[i, :], scales)  #枚举各种尺度,vstack:竖向合并数组  
                             for i in xrange(ratio_anchors.shape[0])]) #shape[0]:读取矩阵第一维长度,其值为3  
        return anchors  
    
    #用于返回width,height,(x,y)中心坐标(对于一个anchor窗口)  
    def _whctrs(anchor):  
        """ 
        Return width, height, x center, and y center for an anchor (window). 
        """  
        #anchor:存储了窗口左上角,右下角的坐标  
        w = anchor[2] - anchor[0] + 1  
        h = anchor[3] - anchor[1] + 1  
        x_ctr = anchor[0] + 0.5 * (w - 1)  #anchor中心点坐标  
        y_ctr = anchor[1] + 0.5 * (h - 1)  
        return w, h, x_ctr, y_ctr  
    
    #给定一组宽高向量,输出各个anchor,即预测窗口,**输出anchor的面积相等,只是宽高比不同**  
    def _mkanchors(ws, hs, x_ctr, y_ctr):  
        #ws:[23 16 11],hs:[12 16 22],ws和hs一一对应。  
        """ 
        Given a vector of widths (ws) and heights (hs) around a center 
        (x_ctr, y_ctr), output a set of anchors (windows). 
        """  
        ws = ws[:, np.newaxis]  #newaxis:将数组转置  
        hs = hs[:, np.newaxis]  
        #hstack、vstack:合并数组,生成三个anchors,宽高比分别为2:1, 1:1, 1:2
        anchors = np.hstack((x_ctr - 0.5 * (ws - 1),      
                             y_ctr - 0.5 * (hs - 1),    #anchor:[[-3.5 2 18.5 13]  
                             x_ctr + 0.5 * (ws - 1),     #        [0  0  15  15]  
                             y_ctr + 0.5 * (hs - 1)))     #       [2.5 -3 12.5 18]]  
        return anchors  
    
    #枚举一个anchor的各种宽高比,anchor[0 0 15 15],ratios[0.5,1,2]  
    def _ratio_enum(anchor, ratios):  
        """   列举关于一个anchor的三种宽高比 1:2,1:1,2:1 
        Enumerate a set of anchors for each aspect ratio wrt an anchor. 
        """  
    
        w, h, x_ctr, y_ctr = _whctrs(anchor)  #返回宽高和中心坐标,w:16,h:16,x_ctr:7.5,y_ctr:7.5  
        size = w * h   #size:16*16=256  
        size_ratios = size / ratios  #256/ratios[0.5,1,2]=[512,256,128]  
        #round()方法返回x的四舍五入的数字,sqrt()方法返回数字x的平方根  
        ws = np.round(np.sqrt(size_ratios)) #ws:[23 16 11]  
        hs = np.round(ws * ratios)    #hs:[12 16 22],ws和hs一一对应。as:23&12  
        anchors = _mkanchors(ws, hs, x_ctr, y_ctr)  #给定一组宽高向量,输出各个预测窗口  
        return anchors  
    
    #枚举一个anchor的各种尺度,以anchor[0 0 15 15]为例,scales[8 16 32]  
    def _scale_enum(anchor, scales):  
        """   列举关于一个anchor的三种尺度 128*128,256*256,512*512 
        Enumerate a set of anchors for each scale wrt an anchor. 
        """  
        w, h, x_ctr, y_ctr = _whctrs(anchor) #返回宽高和中心坐标,w:16,h:16,x_ctr:7.5,y_ctr:7.5  
        ws = w * scales   #[128 256 512]  
        hs = h * scales   #[128 256 512]  
        anchors = _mkanchors(ws, hs, x_ctr, y_ctr) #[[-56 -56 71 71] [-120 -120 135 135] [-248 -248 263 263]]  
        return anchors  
    
    if __name__ == '__main__':  #主函数  
        import time  
        t = time.time()  
        a = generate_anchors()  #生成anchor(窗口)  
        print time.time() - t   #显示时间  
        print a  
        from IPython import embed; embed()  
    

    References

    相关文章

      网友评论

          本文标题:Faster-RCNN如何产生Anchors(generate_

          本文链接:https://www.haomeiwen.com/subject/sognlctx.html